the role of an os or operating system is the program that executes everything and makes the computer usable hope this helps
The Boolean operator OR expands the number of results when used in a keyword search. Thus, the correct option is D.
<h3>What is the Boolean operator?</h3>
The Boolean operator may be defined as an important tool that is utilized in the programming languages for the junctions to integrate or exclude keywords in a search, resulting in more attention and generative outcomes.
The Boolean operators are major of three types with specific functions and properties. They are:
Therefore, the Boolean operator OR expands the number of results when used in a keyword search. Thus, the correct option is D.
To learn more about Boolean operators, refer to the link:
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Answer:
x == 32
Explanation:
CODE in Java:
int x = 32;
if(x == 32){
System.out.println("Pass");
}
else{
System.out.println("Fail");
}
OUTPUT:
Pass
Answer:
Ally typed a business letters she most likely used a <u>Word Processor</u>.
Explanation:
Word processors are the tools that are used to process the text in terms of formatting, printing and editing the text document. These programs or software are used to write the text document with ease.
Microsoft word and word perfect are the examples of the word processors.
We can write the text on note pad as well, but we cannot apply different fonts style, size and formatting techniques on that application. Word processors provide a lot of fonts styles and formatting options to make the document appealing.
Answer:
See the code below and the algorithm explanation on the figure.
Explanation:
The explanation in order to get the answer is given on the figure below.
Solving this problem with C. The program is given below:
#include <stdio.h>
int main(void) {
int n, Even=0, Odd=0, Zeros=0;
for (;;) {
printf("\nEnter the value the value that you want to check(remember just integers): ");
//IF we input a non-numeric character the code end;
if (scanf("%d", &n) != 1) break;
if (n == 0) {
Zeros++;
}
else {
if (n % 2) {
Even++;
}
else {
Odd++;
}
}
}
printf("for this case we have %d even, %d odd, and %d zero values.", Even, Odd, Zeros);
return 0;
}
