knowing your exact credit score. having a rough estimate is good enough
Part 1926 & Part 1910
hope this helps
Answer:
total bits = 6 + 6 + 19 = 31 bits
Explanation:
given data
total registers = 55
memory size = 64 KB
total instructions = 60
solution
here we have given 55 register so we get greater or equal power of 2 that is here 64
so here for register operand 6 bit is required
and
when instruction 60 we get here greater or equal power of 2 that is here 64
so here also for represent instruction 6 bit is required
and
for size 64 kb
= 
so 19 bits is required for memory location
and
as instruction in 2 parts are opcode and operand
and here given as 2 address instruction
they are memory operand and the register operand
so here
total bits will be = opcode + register operand + memory operand
total bits = 6 + 6 + 19 = 31 bits
total bits = 31 bits
Answer:
Explanation:
public void rotate()
{
if(front == null)
return;
ListNode current = front;
ListNode firstNode = current;
while(current.next != null)
{
current = current.next;
}
current.next = front;
front = firstNode.next;
firstNode.next = null;
}
Answer:
101.1
Explanation:
Keep in mind that octal has 8 numbers
Step 1: Split your number in 2 parts (integer part and decimal part):
- integer part 65
- decimal part 0.125
Step 2: Convert the decimal part. For this step you need to multiply your decimal part and 8 (8 correspond the octal base) and get the integer part until you need it:
0.125 * 8 = 1
So your decimal part correspond to number 1 in octal = (1)8
Step 3: Convert integer part: for this step you need to divide your integer part by 8 until you can and get the remainder
65 / 8 = 8 remainder 1
8 / 8 = 1 remainder 0
1 / 8 = 0 remainder 1
Step 4: join the remainders from bottom to top and get the integer part
101
Step 5: join the integer part and the decimal part to get the octal convertion
101.1
