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2 years ago

What is the domain of the function f(x)=4x-16

Mathematics

1 answer:

Georgia [21]2 years ago

6 0

The domain is the x values, and it is infinitive because a line extends infinitely.

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Determine whether y = -2x² - 3 is a function.

Alexus [3.1K]

Answer:yes

Step-by-step explanation:

5 0

1 year ago

Which of these limits evaluate to 0?

Vikentia [17]

<h3>Answer: C) I and II only</h3>

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Work Shown:

Part I

$\displaystyle \lim_{x \to 2}\frac{x-2}{x+2} = \frac{2-2}{2+2}\\\\\\\displaystyle \lim_{x \to 2}\frac{x-2}{x+2} = \frac{0}{4}\\\\\\\displaystyle \lim_{x \to 2}\frac{x-2}{x+2} = 0\\\\\\$

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Part II

$\displaystyle \lim_{x \to 0}\frac{\sin(x)}{x+2} = \frac{\sin(0)}{0+2}\\\\\\\displaystyle \lim_{x \to 0}\frac{\sin(x)}{x+2} = \frac{0}{2}\\\\\\\displaystyle \lim_{x \to 0}\frac{\sin(x)}{x+2} = 0\\\\\\$

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Part III

$\displaystyle \lim_{x \to 5}\frac{x}{x} = \lim_{x \to 5}1\\\\\\\displaystyle \lim_{x \to 5}\frac{x}{x} = 1\\\\\\$

7 0

2 years ago

Which of these answers best describes the core?

lesya [120]

Full question plzz we need to know what the core is

6 0

2 years ago

Solve 2x2 – 6x + 10 = 0 by completing the square.

Ugo [173]

Answer:

Step-by-step explanation:

2x^2-6x+10=0

2(x^2-3x)+10=0

2(x-(3/2))^2-9/4)+10=0

2(x-(3/2))^2+10-9/2=0

2(x-(3/2))^2+(20-9)/2=0

2(x-(3/2))^2+11/2=0

2(x-(3/2))^2=-11/2

square is always positive so there is no solution

5 0

2 years ago

Solve the proportion.<br> 4<br> y<br> =<br> 7<br> ?<br> y =

Leni [432]

Answer:

y=28/5

Step-by-step explanation:

Okay so for this we can use cross- multiplication. Basically, the product of the numerator of the first number and the denominator of the second is equal to the product of the denominator of the first and the numerator of the second.

What I mean is: 4*7=5*y

so,

28=5y

y=28/5

4 0

2 years ago