Answer:
As per the statement:
Hawick is 15 miles south of Abbotsford, and Kelso is 17 miles east of Abbotsford.
Let H represents Hawick , A represents Abbotsford and K represents Kelso
See the diagram as shown below:
Distance of AH = 15 miles
Distance of AK = 17 miles.
We have to find the distance HK:
Using Pythagoras theorem;
then;
or
miles.
Therefore, the distance from Hawick to Kelso( to the nearest tenth place) is 22.6 miles
Answer:
yes
Step-by-step explanation:
you put answer in end
Answer:
38.13 m^2
Step-by-step explanation:
the area of a triangle =b*h/2
b=base
h=height
area triangle=(4m*3m)/2=(12m^2)/2=6m^2
the area of a rectangle =b*h
b=base
h=height
area of a rectangle=6m*3m=18m^2
area of a semi circle=(pi*r^2)/2
r=radius
area of a semi circle==(3.14*(3m)^2)/2=14.13m^2
area of the figure=6m^2+18m^2+14.13m^2=38.13m^2
the answer is 38.13m^2