Maria starts at a distance of 10 from where Glen starts.
Velocity = distance/time => v=d/t => d=vt
If the distance is measured from starting point,
After time (t),
Maria covers
d-10 =25t => d=25t+10
Glen covers
d=29t
Therefore, C is the correct answer.
Answer:
The two numbers are
and
.
Step-by-step explanation:
I am assuming you meant "numbers", otherwise you question has no answer.
Let us call the two numbers
and
, then we have
(1).
<em>(they multiply to -5)</em>
(2).
<em> (they add to 6}</em>
We solve for
and
, by first solving for
in equation (1):
![a = -\dfrac{5}{b}](https://tex.z-dn.net/?f=a%20%3D%20-%5Cdfrac%7B5%7D%7Bb%7D)
and substituting this value into equation (2):
![-\dfrac{5}{b}+ b =6](https://tex.z-dn.net/?f=-%5Cdfrac%7B5%7D%7Bb%7D%2B%20b%20%3D6)
multiply both sides by
and rearrange to get:
![-5+b^2 =6b](https://tex.z-dn.net/?f=-5%2Bb%5E2%20%3D6b)
![b^2-6b-5=0](https://tex.z-dn.net/?f=b%5E2-6b-5%3D0)
Using the quadratic formula we solve for
to get:
![b = 3+ \sqrt{14}](https://tex.z-dn.net/?f=b%20%3D%203%2B%20%5Csqrt%7B14%7D)
![b =3-\sqrt{14}](https://tex.z-dn.net/?f=b%20%3D3-%5Csqrt%7B14%7D)
which when put into equation (1) give
![a = 3-\sqrt{14}](https://tex.z-dn.net/?f=a%20%3D%203-%5Csqrt%7B14%7D)
.
Thus, the two numbers are
and
.
JP=MB
XP=QB
P=B
J=M
This is because every letter in the triangle notation is respective to one another
Answer:
1536
Step-by-step explanation:
The pattern of the sequence is that the number doubles every single time.
Just double the number until you get to the 10th number of the sequence.
3, 6, 12, 24, 48, 96, 192, 384, 768, 1536
<u>Please</u><u> give</u><u> brainliest</u><u> if</u><u> I</u><u> helped</u><u>!</u><u> </u><u>:</u><u>)</u>
Answer:
AB+AC
Step-by-step explanation:
Given: ![\frac{BX}{XC}=\frac{AB}{AC}](https://tex.z-dn.net/?f=%20%5Cfrac%7BBX%7D%7BXC%7D%3D%5Cfrac%7BAB%7D%7BAC%7D)
To determine: (BX+XC) : XC =? : AC
We need to find ? here
We have
![\frac{BX}{XC}=\frac{AB}{AC}](https://tex.z-dn.net/?f=%20%5Cfrac%7BBX%7D%7BXC%7D%3D%5Cfrac%7BAB%7D%7BAC%7D)
Add 1 both sides
![\frac{BX}{XC}+1=\frac{AB}{AC}+1](https://tex.z-dn.net/?f=%20%5Cfrac%7BBX%7D%7BXC%7D%2B1%3D%5Cfrac%7BAB%7D%7BAC%7D%2B1)
Taking LCM and simplify it
![\frac{BX+XC}{XC}=\frac{AB+AC}{AC}](https://tex.z-dn.net/?f=%5Cfrac%7BBX%2BXC%7D%7BXC%7D%3D%5Cfrac%7BAB%2BAC%7D%7BAC%7D)
We can write fraction as ration
(BX+XC) : XC= (AB+AC) : AC
At place of "?" we get AB+AC
Thus, option 3 is correct. AB+AC