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ale4655 [162]
3 years ago
14

A.S.A.P PLEASE HELP

Mathematics
1 answer:
Monica [59]3 years ago
4 0
To solve this problem yu must apply the proccedure shown below:

 1. You have that the <span>focus of the parabola is located at (0,–2) and the directrix is represented by y=2. Therefore, you have:
</span>
 √(x0-0)²+(y0-(-2))²=|y-2|

 2. By simplifying and clearing x², you obtain:

 (√x0²+(y0+2)²)²=(y0-2)²
 x0²+(y0+2)²=(y0-2)²

 { Note: x0²=x and y0=y)

 x²=-8y

 The answer is: x²=-8y
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A scale factor of 4. This is a simple dilation problem. 
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4 years ago
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Please help me out!!!!
LuckyWell [14K]

Answer:

the value for x is

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7 0
3 years ago
-3/7, -8/3 and -5/2,-2 slope
Alja [10]
So the points are (-3/7,-8/3) and (-5/2,-2)
to find the slope do
(y2-y1)/(x2-x1)
(x,y)
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subsitute
\frac{-2-( \frac{-8}{3} )}{ \frac{-5}{2} - \frac{-3}{7} }
simplify by finding similar denomenators
\frac{\frac{-6}{3}-( \frac{-8}{3} )}{ \frac{-35}{14} - \frac{-6}{14} }
\frac{\frac{-6}{3}( \frac{8}{3} )}{ \frac{-35}{14} + \frac{6}{14} }
add
\frac{\frac{2}{3}}{ \frac{-29}{14}}
multiply top and bottom by \frac{-14}{29
\frac{\frac{-28}{87}}{1}
\frac{-28}{87}
answer is
slope=\frac{-28}{87}


8 0
3 years ago
Which of the following is an example of normal data?​
saveliy_v [14]

Answer:

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Step-by-step explanation:

hope this will help you

5 0
3 years ago
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Which quadratic function has a leading coefficient of 2 and a constant term of –3?
Romashka [77]
The answer is <span>f(x) = 2x2 + 3x – 3
</span>
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a - the leading coefficient
c - the constant term

<u>We are looking for a = 2, c = -3</u>

Through the process of elimination:
The first (f(x) = 2x3 – 3) and the third choice (f(x) = –3x3 + 2) have x³ so these are not quadratic function.

In the function: <span>f(x) = –3x2 – 3x + 2
</span>a = -3
c = 2

In the function: f(x) = 2x2 + 3x – 3
a = 2
c = -3
6 0
3 years ago
Read 2 more answers
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