Answer:
77
Step-by-step explanation:
HAV A GREAT DAY hope this helps
There are total 10 juice boxes
P(grape) first pick:
2/10=1/5
P(grape) second pick:
1/9
As a result, the probability that, when Jill reaches into the cooler to grab two juice boxes without replacing them, she grabs two that are grape is 1/45. Hope it help!
Answer:
B
Step-by-step explanation:
The number is between 10 and 49
The number is divisible by 3
Let the 10s digit = x
Let the units digit = y
1/3 * (10x + y) = x + y multiply both sides by 3
10x + y = 3(x +y) remove the brackets.
10x +y = 3x + 3y Subtract 3x from both sides
10x - 3x + y = 3y Combine\
7x + y = 3y Subtract y from both sides.
7x = 3y - y Combine
7x = 2y
x can't be very big. Even taking 1/3 will get out of range is you use 6.
Also x should be an even number. The units digit cannot have a fraction in it.
Try making x = 2
7*2 = 2*y
14 = 2y Divide by 2
14/2 = y
y = 7
So the number is possibly 27. Let's check it out.
- The number is between and includes 10 and 49. 27 is between these two endpoints.
- 27 is divisible by 3
- 1/3(27) = sum of digits
- 9 = (2 + 7)
All of the conditions are met. It's B
Answer:
0.29
Step-by-step explanation:
Given :
n : ___ 0 _____ 1 ____ 2 ____ 3 ____ 4
P(n) : 0.82___ 0.11 ___0.04 _0.02 ___0.01
The expected number of defect in a shipment can be obtained using the expected value formula :
Expected value, E(X) = Σx*p(x)
Σx*p(x) = (0*0.82) + (1*0.11) + (2*0.04) + (3*0.02) + (4*0.01)
E(X) = 0.29
Hence, the expected number of defect in shipment is 0.29
