3 years ago

Help!

Mathematics

1 answer:

TEA [102]3 years ago

5 0

Multiply both sides by 10...
So u = 50/11 = 4.5454... = 4.55

You might be interested in

A police car leaves a crime scene heading east directly towards the hospital at 72 kilometres per hour. An ambulance leaves a qu

Vaselesa [24]

Answer:

I'm not sure what the answer is but I will tell you when I get it

8 0

3 years ago

What is the percentage of 67

Klio2033 [76]

100% of 67 equals 67

7 0

3 years ago

Im Giving Brainliest............. Someone Plzz Help?

Alekssandra [29.7K]

Answer:

For the first one 25.925%

The second is 23.333%

The third is 27.27%

Let me know if this helps!

6 0

3 years ago

How many times does six.go into Eight

never [62]

Only one time...............

5 0

4 years ago

Read 2 more answers

a) find center of mass of a solid of constant density bounded below by the paraboloid z=x^2+y^2 and above by the plane z=4.(b) F

slava [35]

Answer: x-bar = y-bar = 0 whereas z-bar = 8/3

M= (c^2)/8 which is intern equal to 2 $\sqrt{2}$

Step-by-step explanation:

Find the area, by setting the limits as

= $4\cdot \int _0^{\frac{\pi }{2}}\int _0^2\int _{r^2}^4\:rdzdrd\theta$

$=4\cdot \int _0^{\frac{\pi }{2}}\int _0^2r\cdot \:4-r^3drd\theta$

$=4\cdot \int _0^{\frac{\pi }{2}}4d\theta$

$=8\pi$

Therefore;

Mxy= $\int _0^{2\pi }\int _0^2\int _{r^2}^4\:zrdzdrd\theta$

z-bar = 8/3

M= 8 $\pi$ dividing it into two volume gives us = 4 $\pi$

means $4\pi =\int _0^{2\pi }\int _0^{\sqrt{c}}\int _r^c\:rdzdrd\theta$

$4\pi =\left(\pi c^2-2\pi \frac{c^{\frac{3}{2}}}{3}\right)$

c=2 $\sqrt{2}$

5 0

3 years ago