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Umnica [9.8K]
3 years ago
15

PLEASE HELP picture below!!!

Mathematics
2 answers:
SCORPION-xisa [38]3 years ago
7 0

Answer: x=5

Step-by-step explanation:

8x+50=90

then you use the subtraction property of equality to get 8x=40

then you use the division property of equality to get x=5

faust18 [17]3 years ago
5 0

Answer:

I am not sure about this one, but probably 5

Step-by-step explanation:remember the square is 90 deg. and you already have 50 so you need 40 more and 8 times 5= 40

You might be interested in
Graph the image of the given triangle under a dilation with a scale factor of 12 and center of dilation ​ (0, 0)
AysviL [449]

Answer:Graph the image of the given triangle under a dilation with a scale factor of 12 and center of dilation ​ (0, 0)

4 0
3 years ago
Three kids play tennis at the same tennis courts. Mark plays every fourth day, David plays every seventh day and Bryan plays eve
jonny [76]

Answer:

Wednesday (9 weeks later) = 10th October.

Step-by-step explanation:

We label the days with the initials of the names.

M= 4

D = 7

B = 6

LCM of 6 +7 = 42

LCM of 6+7 + 4 = 84

We find 84 is the amount of days we need to add on to july 18th

We first find the weeks 84/7 = 9 weeks.

As Wednesday July 18th is exclusive it would be 84 days after this event.

18+ 84 = 102 days.

31 days in july = 31

31 days in Aug = 31

30 days in Sept = 30

= 92

102-92 = 10

We now know date is Wednesday 10th October

We can check 84 days = 9 weeks

13 days in July makes 31st july

31 days in Aug makes 31st Aug

30 days in Sept makes 30th Sept

= 74 days + 10 days = 84

10th October is the checked date and we know it is also a Wednesday as Wednesday had stayed exclusive and prove that there are 7 days in the week to account x 9, to account for an exact 9 weeks later duration.

6 0
3 years ago
Read 2 more answers
Next Question!
rodikova [14]

Answer:

1/6≈0.17≈17%

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
This is a "water tank" calculus problem that I've been working on and I would really appreciate it if someone could look at my w
Sedaia [141]
Part A

Everything looks good but line 4. You need to put all of the "2h" in parenthesis so the teacher will know you are squaring all of 2h. As you have it right now, you are saying "only square the h, not the 2". Be careful as silly mistakes like this will often cost you points. 

============================================================

Part B

It looks like you have the right answer. Though you'll need to use parenthesis to ensure that all of "75t/(2pi)" is under the cube root. I'm assuming you made a typo or forgot to put the parenthesis. 

dh/dt = (25)/(2pi*h^2)
2pi*h^2*dh = 25*dt
int[ 2pi*h^2*dh ] = int[ 25*dt ] ... applying integral to both sides
(2/3)pi*h^3 = 25t + C
2pi*h^3 = 3(25t + C)
h^3 = (3(25t + C))/(2pi)
h^3 = (75t + 3C)/(2pi)
h^3 = (75t + C)/(2pi)
h = [ (75t + C)/(2pi) ]^(1/3)

Plug in the initial conditions. If the volume is V = 0 then the height is h = 0 at time t = 0
0 = [ (75(0) + C)/(2pi) ]^(1/3)
0 = [ (0 + C)/(2pi) ]^(1/3)
0 = [ (C)/(2pi) ]^(1/3)
0^3 =  (C)/(2pi)
0 = C/(2pi)
C/(2pi) = 0
C = 0*2pi
C = 0 

Therefore the h(t) function is...
h(t) = [ (75t + C)/(2pi) ]^(1/3)
h(t) = [ (75t + 0)/(2pi) ]^(1/3)
h(t) = [ (75t)/(2pi) ]^(1/3)

Answer:
h(t) = [ (75t)/(2pi) ]^(1/3)

============================================================

Part C

Your answer is correct. 
Below is an alternative way to find the same answer

--------------------------------------

Plug in the given height; solve for t
h(t) = [ (75t)/(2pi) ]^(1/3)
8 = [ (75t)/(2pi) ]^(1/3)
8^3 = (75t)/(2pi)
512 = (75t)/(2pi)
(75t)/(2pi) = 512
75t = 512*2pi
75t = 1024pi
t = 1024pi/75
At this time value, the height of the water is 8 feet

Set up the radius r(t) function 
r = 2*h
r = 2*h(t)
r = 2*[ (75t)/(2pi) ]^(1/3) .... using the answer from part B

Differentiate that r(t) function with respect to t
r = 2*[ (75t)/(2pi) ]^(1/3)
dr/dt = 2*(1/3)*[ (75t)/(2pi) ]^(1/3-1)*d/dt[(75t)/(2pi)] 
dr/dt = (2/3)*[ (75t)/(2pi) ]^(-2/3)*(75/(2pi))
dr/dt = (2/3)*(75/(2pi))*[ (75t)/(2pi) ]^(-2/3)
dr/dt = (25/pi)*[ (75t)/(2pi) ]^(-2/3)

Plug in t = 1024pi/75 found earlier above
dr/dt = (25/pi)*[ (75t)/(2pi) ]^(-2/3)
dr/dt = (25/pi)*[ (75(1024pi/75))/(2pi) ]^(-2/3)
dr/dt = (25/pi)*[ (1024pi)/(2pi) ]^(-2/3)
dr/dt = (25/pi)*(1/64)
dr/dt = 25/(64pi)
getting the same answer as before

----------------------------

Thinking back as I finish up, your method is definitely shorter and more efficient. So I prefer your method, which is effectively this:
r = 2h, dr/dh = 2
dh/dt = (25)/(2pi*h^2) ... from part A
dr/dt = dr/dh*dh/dt ... chain rule
dr/dt = 2*((25)/(2pi*h^2))
dr/dt = ((25)/(pi*h^2))
dr/dt = ((25)/(pi*8^2)) ... plugging in h = 8
dr/dt = (25)/(64pi)
which is what you stated in your screenshot (though I added on the line dr/dt = dr/dh*dh/dt to show the chain rule in action)
8 0
3 years ago
A movie theater charges $10 and 50 cent per ticket and five dollars per bucket of popcorn.You never buy the popcorn because you
cestrela7 [59]

Answer: Yes


Step-by-step explanation:

Yes it is, your ratio would be 10.50:1

$10.50 spent on every one ticket. if you buy more than one, a fraction would still simplify down to 10.50/1.

if you were to buy the popcorn then no it wouldn't be.

7 0
3 years ago
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