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3 years ago

PLEASE HELP picture below!!!

Mathematics

2 answers:

SCORPION-xisa [38]3 years ago

7 0

Answer: x=5

Step-by-step explanation:

8x+50=90

then you use the subtraction property of equality to get 8x=40

then you use the division property of equality to get x=5

faust18 [17]3 years ago

5 0

Answer:

I am not sure about this one, but probably 5

Step-by-step explanation:remember the square is 90 deg. and you already have 50 so you need 40 more and 8 times 5= 40

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Find the exact length of the curve. x=et+e−t, y=5−2t, 0≤t≤2 For a curve given by parametric equations x=f(t) and y=g(t), arc len

Rama09 [41]

The length of a curve C parameterized by a vector function r(t) = x(t) i + y(t) j over an interval a ≤ t ≤ b is

$\displaystyle\int_C\mathrm ds = \int_a^b \sqrt{\left(\frac{\mathrm dx}{\mathrm dt}\right)^2+\left(\frac{\mathrm dy}{\mathrm dt}\right)^2} \,\mathrm dt$

In this case, we have

x(t) = exp(t ) + exp(-t ) ==> dx/dt = exp(t ) - exp(-t )

y(t) = 5 - 2t ==> dy/dt = -2

and [a, b] = [0, 2]. The length of the curve is then

$\displaystyle\int_0^2 \sqrt{\left(e^t-e^{-t}\right)^2+(-2)^2} \,\mathrm dt = \int_0^2 \sqrt{e^{2t}-2+e^{-2t}+4}\,\mathrm dt$

$=\displaystyle\int_0^2 \sqrt{e^{2t}+2+e^{-2t}} \,\mathrm dt$

$=\displaystyle\int_0^2\sqrt{\left(e^t+e^{-t}\right)^2} \,\mathrm dt$

$=\displaystyle\int_0^2\left(e^t+e^{-t}\right)\,\mathrm dt$

$=\left(e^t-e^{-t}\right)\bigg|_0^2 = \left(e^2-e^{-2}\right)-\left(e^0-e^{-0}\right) = \boxed{e^2-\frac1{e^2}}$

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3 years ago

which equations are equivalent to 3/4+m=-7/4 check all that apply m=10/4 m=-10/4 m=-5/2 11/4+m=-1/4 -5/4+m=-15/4 m+2=-0.5 Help f

Alecsey [184]

Answer:

The correct choices are; B,C,E, and F.

Step-by-step explanation:

The given equation is;

$\frac{3}{4}+m=-\frac{7}{4}$

We solve for m to obtain:

$m=-\frac{7}{4}-\frac{3}{4}=-2.5$

We also solve the remaining equations to see which ones give the same result.

A: $m=\frac{10}{4} =2.5$

B: $m=-\frac{10}{4} =-2.5$

C: $m=-\frac{5}{2} =-2.5$

D: $\frac{11}{4}+m=-\frac{1}{4}$

$m=-\frac{1}{4}-\frac{11}{4}=-3$

E: $-\frac{5}{4}+m=-\frac{15}{4}$

$m=-\frac{15}{4}+\frac{5}{4}=-2.5$

F: $m+2=-0.5$

$m=-0.5-2=-2.5$

The equivalent equations are; B,C,E, and F.

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