Answer:
(- 3.5, - 5.5 )
Step-by-step explanation:
Given the 2 equations
y = x - 2 → (1)
y = 3x + 5 → (2)
Substitute y = 3x + 5 into (1)
3x + 5 = x - 2 ( subtract x from both sides )
2x + 5 = - 2 ( subtract 5 from both sides )
2x = - 7 ( divide both sides by 2 )
x = - 3.5
Substitute x = - 3.5 into either of the 2 equations and evaluate for y
Substituting into (1)
y = - 3.5 - 2 = - 5.5
Solution is (- 3.5, - 5.5 )
Seeing as this is a right triangle, we would solve for the unknown angle using a trigonometric function.
Remember! SOH-CAH-TOA
Looking from the unknown angle, we are given the adjacent side and the hypotenuse. Therefore, we should use the cosine function.
cos(?) = 17 / 19
---To find the unknown angle measure, you will need to use the inverse cosine function. This function is generally found by using the "2nd" button on your calculator and then pressing the cosine button. It should look like one of the following options: "cos^-1" or "arccos".
Make sure your calculator is in degrees, not radians!
cos^(-1) [17/`9]
26.52
---Round to the nearest degree per the instructions
Answer: 27 degrees
Hope this helps!
Answer:
Both answers are B
ar(ΔABO) = ar(ΔCDO)
Explanation:
The image attached below.
Given ABCD is a trapezoid with legs AB and CD.
AB and CD are non-parallel sides between the parallels AD and BC.
In ΔABD and ΔACD,
We know that, triangles lie between the same base and same parallels are equal in area.
⇒ AD is the common base for ΔABD and ΔACD and they are lie between the same parallels AD and BC.
Hence, ar(ΔABD) = ar(ΔACD) – – – – (1)
Now consider ΔABO and ΔCDO,
Subtract ar(ΔAOD) on both sides of (1), we get
ar(ΔABD) – ar(ΔAOD) = ar(ΔACD) – ar(ΔAOD)
⇒ar(ΔABO) = ar(ΔCDO)
Hence, ar(ΔABO) = ar(ΔCDO).
Answer:
It's option D. 8(8x + 9y).
