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2 years ago

This statement is justified by which property of equality?

Mathematics

1 answer:

Galina-37 [17]2 years ago

4 0

Answer:

symmetric property

Step-by-step explanation:

with symmetric property if x=y then both values on either side of the equal sign will be equal

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Don works in home construction. He determined that the function t(A)=144A/9.252 gives the total number of 9 in. tiles needed to

Oksanka [162]

Answer:

6,226 tiles of 9 in are needed to cover an area of 400 square feet

Step-by-step explanation:

Let

A -----> an area in square feet

t(A) ---> the total number of 9 in. tiles needed

we have

$t(A)=\frac{144A}{9.252}$

For A=400 ft^2

substitute in the equation and solve for t

$t(400)=\frac{144(400)}{9.252}$

$t(400)=6,226\ tiles$

That means -----> 6,226 tiles of 9 in are needed to cover an area of 400 square feet

6 0

2 years ago

Identifying roots - Pre calculus stuff

umka2103 [35]

The answers are 0 and 2

This can be found by looking at the x axis and finding every point where the line crosses

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3 years ago

−6x^2−1 and x+9 help will mark brainliest.

Varvara68 [4.7K]

Answer:

-6x^2+x+8

Step-by-step explanation:

Add -1 and 9 because they are the only like terms

8 0

2 years ago

What is 2/3÷-3/5 as an improper fraction

rodikova [14]

Answer: -10/9

Step-by-step explanation: is this what you were looking for

8 0

3 years ago

A bag contains different colored candies. There are 50 candies in the bag, 28 are red, 10 are blue, 8 are green and 4 are yellow

Mrrafil [7]

Answer:

$\displaystyle \frac{54}{5405}$ .

Step-by-step explanation:

How many unique combinations are possible in total?

This question takes 5 objects randomly out of a bag of 50 objects. The order in which these objects come out doesn't matter. Therefore, the number of unique choices possible will the sames as the combination

$\displaystyle \left(50\atop 5\right) = 2,118,760$ .

How many out of that 2,118,760 combinations will satisfy the request?

Number of ways to choose 2 red candies out a batch of 28:

$\displaystyle \left( 28\atop 2\right) = 378$ .

Number of ways to choose 3 green candies out of a batch of 8:

$\displaystyle \left(8\atop 3\right)=56$ .

However, choosing two red candies out of a batch of 28 red candies does not influence the number of ways of choosing three green candies out of a batch of 8 green candies. The number of ways of choosing 2 red candies and 3 green candies will be the product of the two numbers of ways of choosing

$\displaystyle \left( 28\atop 2\right) \cdot \left(8\atop 3\right) = 378\times 56 = 21,168$ .

The probability that the 5 candies chosen out of the 50 contain 2 red and 3 green will be:

$\displaystyle \frac{21,168}{2,118,760} = \frac{54}{5405}$ .

3 0

3 years ago