Answer:
a) ![S_{a}(t)=16Kg-0.16Kg*\frac{t}{min}](https://tex.z-dn.net/?f=S_%7Ba%7D%28t%29%3D16Kg-0.16Kg%2A%5Cfrac%7Bt%7D%7Bmin%7D)
b) ![S_{a}(20)=12.8Kg](https://tex.z-dn.net/?f=S_%7Ba%7D%2820%29%3D12.8Kg)
Step-by-step explanation:
It can be seen in the graph that the water velocity and solution velocity is the same, but the salt concentation will be lower
Water velocity ![V_{w} = 60\frac{L}{min}](https://tex.z-dn.net/?f=V_%7Bw%7D%20%3D%2060%5Cfrac%7BL%7D%7Bmin%7D)
Solution velocity ![V_{s} = 60\frac{L}{min}](https://tex.z-dn.net/?f=V_%7Bs%7D%20%3D%2060%5Cfrac%7BL%7D%7Bmin%7D)
Brine concentration = ![\frac{6,000L}{16Kg}=375\frac{L}{Kg}](https://tex.z-dn.net/?f=%5Cfrac%7B6%2C000L%7D%7B16Kg%7D%3D375%5Cfrac%7BL%7D%7BKg%7D)
a) Amount of salt as a funtion of time Sa(t)
![S_{a}(t)=16Kg-\frac{60Kg*L}{375L}*\frac{(t)}{min}=[tex]16Kg-0.16Kg*\frac{t}{min}](https://tex.z-dn.net/?f=S_%7Ba%7D%28t%29%3D16Kg-%5Cfrac%7B60Kg%2AL%7D%7B375L%7D%2A%5Cfrac%7B%28t%29%7D%7Bmin%7D%3D%5Btex%5D16Kg-0.16Kg%2A%5Cfrac%7Bt%7D%7Bmin%7D)
b) ![S_{a}(20)=16Kg-0.16\frac{Kg}{min}*(20min)=16Kg-3.2Kg=12.8Kg](https://tex.z-dn.net/?f=S_%7Ba%7D%2820%29%3D16Kg-0.16%5Cfrac%7BKg%7D%7Bmin%7D%2A%2820min%29%3D16Kg-3.2Kg%3D12.8Kg)
This value was to be expected since as the time passes the concentration will be lower due to the entrance to the pure water tank
Answer:
232 sq. m
Step-by-step explanation:
Answer:
5 + 2.5x <20
Step-by-step explanation:
subtract 5 from each side so now it is 2.5x < 15
divide both sides by 2.5, so now it is x < 6
so it will be LESS THAN 6 months before her hair is LESS THAN 20 centimeters
3+1/x *x = 7/x*x
3x+1 = 7
3x+1-1=7-1
3x=6
3x/3 =6/3
x =2