Answer:
Log₆ (A⁵C² / D⁶) = –13
Step-by-step explanation:
From the question given above,
Log₆ A = 1
Log₆ C = 3
Log₆ D = 4
Log₆ (A⁵C² / D⁶) =?
Recall:
Log MN / U = Log M + Log N – Log U
Therefore,
Log₆ (A⁵C² / D⁶) = Log₆ A⁵ + Log₆ C² – Log₆ D⁶
Recall:
Log Mⁿ = nLog M
Thus,
Log₆ A⁵ + Log₆ C² – Log₆ D⁶
= 5Log₆ A + 2Log₆ C – 6Log₆ D
Log₆ A = 1
Log₆ C = 3
Log₆ D = 4
= 5(1) + 2(3) – 6(4)
= 5 + 6 – 24
= 11 – 24
= –13
Therefore,
Log₆ (A⁵C² / D⁶) = –13
44% of 8.79 =
0.44 (8.79) = 3.87 (thats rounded)
8% of 2.36 =
0.08 (2.36) = 0.19 (rounded)
25 students, homework 3 times per week, 12 problems each assignment
3(12) = 36 problems per student...36(25) = 900 problems for 25 students.
ur answer is 900
Perimeter (p) = length around a shape.
So any horizontal sides we can add based upon their length in x-values and any vertical sides we can add based upon their length in y-values. The diagonal sides we can find by the distance formula:

So the bottom base goes from x=1 to x=8, then up 1, right 1, and up from y=3 to y=9, then left from x=9 to x=6, down from y=9 to y=6, left from x=6 to x=3.
So far that is: (8-1)+1+1+(9-3)+(9-6)+(9-6)+(6-3)
= 7+2+6+3+3+3 = 24
Now for the diagonal:

P = 24 + 4.47 = 28.47
D) 28.472
Answer:
The area of LQM is 
Step-by-step explanation:
Given
Area of PNQ = 8
Area of LPQ = 16
See attachment for triangles
The area of PNQ is calculated as:

Substitute 8 for Area


The area of LPQ is calculated as:

Substitute 16 for Area

From the attachment:

Make LP the subject

So:

We have:
and 
Equate both expressions:

Divide both sides by PQ

Multiply both sides by 2


Since PNQ is similar to LNM, the following equivalent ratios exist:

Substitute 



Area of LQM is:

This gives:


Recall that:

So:

