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oksian1 [2.3K]
3 years ago
13

What is the amplitude of y=1/2sin2x

Mathematics
1 answer:
rusak2 [61]3 years ago
7 0
The multiplier of the sine function is its amplitude: 1/2.
You might be interested in
Question 1 of 10
Darya [45]

Answer:

Log₆ (A⁵C² / D⁶) = –13

Step-by-step explanation:

From the question given above,

Log₆ A = 1

Log₆ C = 3

Log₆ D = 4

Log₆ (A⁵C² / D⁶) =?

Recall:

Log MN / U = Log M + Log N – Log U

Therefore,

Log₆ (A⁵C² / D⁶) = Log₆ A⁵ + Log₆ C² – Log₆ D⁶

Recall:

Log Mⁿ = nLog M

Thus,

Log₆ A⁵ + Log₆ C² – Log₆ D⁶

= 5Log₆ A + 2Log₆ C – 6Log₆ D

Log₆ A = 1

Log₆ C = 3

Log₆ D = 4

= 5(1) + 2(3) – 6(4)

= 5 + 6 – 24

= 11 – 24

= –13

Therefore,

Log₆ (A⁵C² / D⁶) = –13

7 0
2 years ago
Derricks dog sitting and darlene's dog sitting are competing for new business. The companies ran the ads shown.
raketka [301]
This question dont make sense
7 0
3 years ago
find 44% of 8.79. user: find 8% of 2.36. user: darren teaches a class of 25 students. he assigns homework 3 times a week, and ea
Andrews [41]
44% of 8.79 = 
0.44 (8.79) = 3.87 (thats rounded) 

8% of 2.36 =
0.08 (2.36) = 0.19 (rounded)

25 students, homework 3 times per week, 12 problems each assignment 
3(12) = 36 problems per student...36(25) = 900 problems for 25 students.
ur answer is 900

7 0
3 years ago
What is the perimeter of the figure in the diagram (round to three decimal places if necessary)?
Y_Kistochka [10]
Perimeter (p) = length around a shape.
So any horizontal sides we can add based upon their length in x-values and any vertical sides we can add based upon their length in y-values. The diagonal sides we can find by the distance formula:
d =  \sqrt{( {(x2 - x1)}^{2}  +  {(y2 - y1)}^{2} }
So the bottom base goes from x=1 to x=8, then up 1, right 1, and up from y=3 to y=9, then left from x=9 to x=6, down from y=9 to y=6, left from x=6 to x=3.
So far that is: (8-1)+1+1+(9-3)+(9-6)+(9-6)+(6-3)
= 7+2+6+3+3+3 = 24
Now for the diagonal:
d =  \sqrt{( {(x2 - x1)}^{2}  +  {(y2 - y1)}^{2}) }  \\  =  \sqrt{( {(3- 1)}^{2}  +  {(6 - 2)}^{2} )}  \\  =  \sqrt{( {2}^{2}  +  {4}^{2} )}  =  \sqrt{(4 + 16)} \\  =  \sqrt{20} = 2 \sqrt{5}  = 4.47
P = 24 + 4.47 = 28.47
D) 28.472

4 0
3 years ago
Read 2 more answers
LMN is a right-angle triangle. Angle NLM=90. PQ is parallel to LM. The area of triangle PNQ is 8cm^2. The area of triangle LPQ i
likoan [24]

Answer:

The area of LQM is 48cm^2

Step-by-step explanation:

Given

Area of PNQ = 8

Area of LPQ = 16

See attachment for triangles

The area of PNQ is calculated as:

Area = \frac{1}{2} * PQ * PN

Substitute 8 for Area

8 = \frac{1}{2} * PQ * PN

PQ * PN = 16

The area of LPQ is calculated as:

Area = \frac{1}{2} * PQ * LP

Substitute 16 for Area

16= \frac{1}{2} * PQ * LP

From the attachment:

PN + LP =LN

Make LP the subject

LP = LN -PN

So:

16= \frac{1}{2} * PQ * (LN -PN)

We have:

16= \frac{1}{2} * PQ * (LN -PN) and PQ * PN = 16

Equate both expressions:

\frac{1}{2} * PQ *(LN - PN) = PQ * PN

Divide both sides by PQ

\frac{1}{2} (LN - PN) = PN

Multiply both sides by 2

LN - PN = 2PN

LN= 3PN

Since PNQ is similar to LNM, the following equivalent ratios exist:

\frac{LM}{PQ} = \frac{LN}{PN}

Substitute LN= 3PN

\frac{LM}{PQ} = \frac{3PN}{PN}

\frac{LM}{PQ} = 3

LM = 3PQ

Area of LQM is:

Area = \frac{1}{2} * LM * LP

This gives:

Area = \frac{1}{2} * 3PQ * LP

Area = 3 *\frac{1}{2} *PQ * LP

Recall that:

16= \frac{1}{2} * PQ * LP

So:

Area = 3 *16

Area = 48cm^2

5 0
3 years ago
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