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3 years ago

Please guys help me with this. I will give you brainliest. please ❤❤

Mathematics

2 answers:

Alchen [17]3 years ago

7 0

Answer:

Step-by-step explanation:

Look Closely at the support and knowledge then you get your answer there.

❤❤

yawa3891 [41]3 years ago

4 0

Answer:

. ........

Step-by-step explanation:

may i know were is the question??

lol

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Katie has 1/6 of watermelon left over from her picnic that she wants to split between her mom and dad. How much watermelon will

frozen [14]

Answer: 1/12 of a watermelon

Each parent will get one half of 1/6 each.
1/2 x 1/6 = 1/12

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4 years ago

Which of the following linear equations describes that relationship?

JulsSmile [24]

Answer:

D. f(x) = 4x - 3

Step-by-step explanation:

Use two pairs of points to work out the equation:

(1, 1) and (2, 5)

Find the slope:

m = (5 - 1) / (2 - 1) = 4/1 = 4

Find the y-intercept:

1 = 4*1 + b
b = 1 - 4
b = - 3

The line is:

f(x) = 4x - 3

Correct choice is D

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2 years ago

Solve y=1/4x+5 y=2x-9

Goshia [24]

Answer????

Step-by-step explanation:

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3 years ago

Which expression shows the result of applying the distributive property to 3 (1/5x - 1/7)

Ivan

Hi,

3(1/5x - 1/7)

= 3/5x - 3/7

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3 0

2 years ago

A decorative window is made up of a rectangle with semicircles at either end. The ratio of AD to AB is 3:2 and AB is 30 inches.

scZoUnD [109]

Answer: The required ratio will be

$84:1034$

Step-by-step explanation:

Since we have given that

Ratio of AD to AB is 3:2

Length of AB = 30 inches

So, it becomes

$2x=30\\\\x=\frac{30}{2}=15\ inches$

So, Length of AD becomes

$3x=3\times 15=45\ inches$

Now, at either end , there is a semicircle.

Radius of semicircle along AB is given by

$\frac{30}{2}=15\ inches$

So, Area of semicircle along AB and CD is given by

$2\times \frac{\pi r^2}{2}\\\\=\frac{22}{7}\times 15\times 15\\\\=\frac{4950}{7}\ in^2$

Radius of semicircle along AD is given by

$\frac{45}{2}=22.5\ inches$

Area of semicircle along AD and BC is given by

$2\times \frac{1}{2}\pi r^2\\\\=\frac{22}{7}\times \frac{45}{2}\times \frac{45}{2}\\\\=\frac{445500}{28}\ in^2$

And the combined area of the semicircles is given by

$\frac{4950}{7}+\frac{445500}{28}\\\\=\frac{465300}{28}\ in^2$

Area of rectangle is given by

$Length\times width\\\\=AD\times AB\\\\=45\times 30\\\\=1350\ in^2$

Hence, Ratio of the area of the rectangle to the combined area of the semicircles is given by

$1350:\frac{465300}{28}\\\\=1350\times 28:465300\\\\=37800:465300\\\\=84:1034$

Hence, the required ratio will be

$84:1034$

8 0

3 years ago

Please guys help me with this. I will give you brainliest. please ❤❤​

Please guys help me with this. I will give you brainliest. please ❤❤