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Butoxors [25]
3 years ago
9

Help points and Awnser !!

Mathematics
2 answers:
Vsevolod [243]3 years ago
6 0

Answer:

I say 20% but I may be wrong

Step-by-step explanation:

harina [27]3 years ago
6 0
20 percent is right
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F(x) = x5 + (x + 3)2 x=-1
sveticcg [70]
Hello!

You put -1 in for x

F(-1) = (-1)^5 + (-1 + 3)^2

F(-1) = -1 + (2)^2

F(-1) = -1 + 4

F(-1) = 3

The answer is 3

Hope this helps!
8 0
3 years ago
A box contains 4 red and 5 green marbles. if 6 marbles are drawn without replacement, what is the expected number of red marbles
qaws [65]
The expected number is 2 marbles
6 0
3 years ago
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What is 3x + 5y ????
baherus [9]
3x + 5y
Equal it out to zero.
3x + 5y = 0
Lets solve for x first.
3x = -5y
Divide by 3 to get x by itself.
x = -5y/3
Now solve for y.
3x + 5y = 0
Add -3 to both sides.
5y = -3x
Divide both sides by 5.
y = -3/5x

I Sure Hope This Helps!
6 0
3 years ago
I'd love some help <3 !!
Fudgin [204]
Bottom ratio and 18 bags
6 0
2 years ago
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A researcher wanted to see if giving a selective serotonin reuptake inhibitor (anti-depressant) would decrease the number of sel
Delvig [45]

Answer:

a. The mean of the sample is M=35.

The variance of the sample is s^2=39.125.

The standard deviation of the sample is s=6.255.

b. z=-1.6

c. SEM = 2.212

Step-by-step explanation:

The mean of the sample is M=35.

The variance of the sample is s^2=39.125.

The standard deviation of the sample is s=6.255.

<u>Sample mean</u>

<u />M=\dfrac{1}{8}\sum_{i=1}^{8}(27+25+32+40+43+37+35+38)\\\\\\ M=\dfrac{277}{8}=35

<u>Sample variance and standard deviation</u>

<u />s^2=\dfrac{1}{(n-1)}\sum_{i=1}^{8}(x_i-M)^2\\\\\\s^2=\dfrac{1}{7}\cdot [(27-(35))^2+(25-(35))^2+(32-(35))^2+(40-(35))^2+(43-(35))^2+(37-(35))^2+(35-(35))^2+(38-(35))^2]\\\\\\

s^2=\dfrac{1}{7}\cdot [(58.141)+(92.641)+(6.891)+(28.891)+(70.141)+(5.64)+(0.14)+(11.39)]\\\\\            s^2=\dfrac{273.875}{7}=39.125\\\\\\s=\sqrt{39.125}=6.255

b. If the population mean is 45, the z-score for M=35 would be:

z=\dfrac{M-\mu}{\sigma}=\dfrac{35-45}{6.255}=\dfrac{-10}{6.255}=-1.6

c. The standard error of the mean (SEM) of this group is calculated as:

SEM=\dfrac{s}{\sqrt{n}}=\dfrac{6.255}{\sqrt{8}}=\dfrac{6.255}{2.828}=2.212

4 0
3 years ago
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