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madreJ [45]
3 years ago
5

What did Sam Houston get from the Texan victory??

Mathematics
2 answers:
faust18 [17]3 years ago
4 0

Answer: He got to be elected president of the Republic of Texas.

anastassius [24]3 years ago
3 0
Sam Houston became a national celebrity, and the Texans' rallying cries from events of the war, "Remember the Alamo" and "Remember Goliad" became etched into Texan history and legend.
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p is equal to 10.

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the solution is a = -3

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What is the LCD of 7/11a and 11/13a
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7 0
3 years ago
I need help fastttt pleaseeeee
pogonyaev

Answer:

1, x = 80

2, z = 5.6

3, w = 18

Step-by-step explanation:

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Suppose that about 55% of the people who are murdered actually knew the person who committed the murder. Suppose that a detectiv
Lynna [10]

Answer:

24.51% probability that fewer than 21 victims did not know their murderer

Step-by-step explanation:

I am going to approximate the binomial probability distribution to the normal to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 51, p = 0.55

So

\mu = E(X) = np = 51*0.55 = 28.05

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{51*0.55*0.45} = 3.55

What is the probability that fewer than 21 victims did not know their murderer?

That is, more than 30 knew the murdered.

P(X \geq 30 + 0.5) = P(X \geq 30.5), which is 1 subtracted by the pvalue of Z when X = 30.5. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{30.5 - 28.05}{3.55}

Z = 0.69

Z = 0.69 has a pvalue of 0.7549

1 - 0.7549 = 0.2451

24.51% probability that fewer than 21 victims did not know their murderer

8 0
3 years ago
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