3 years ago

Whats the largest number you can make in roman numerails?

Mathematics

1 answer:

swat323 years ago

5 0

MMMMCMXCIX or 4,999 is the largest numer. Roman numerals only go to 1,000

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Please answer number 4 and 5

Anestetic [448]

Answer: 4=G 5=A

Step-by-step explanation:

4: since he has only 1 dime 2 nickels and 1 quarter he cant pull out 2 dimes since he doesn't have them, meaning G is not possible.

5: To solve you have to multiply 2 1/2 and 3 1/4, one way is by creating improper fractions and multiply that way. So you will get 5/2 x 13/4 which will give you 65/8. Simply to get 8 and 1/8

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2 years ago

A teacher gives 5 students a multiple choice test, in which each problem is worth 1 point. The median and mean scores turn out t

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2 years ago

Find the solutions for a triangle with a = 16, c =12, and B = 63º.

maks197457 [2]

Answer:

b. A = 71.6°; C = 45.40°; b =15.0

Step-by-step explanation:

The missing values can be found with the help of the Law of Cosine and properties of triangles:

Side b (Law of Cosine)

$b = \sqrt{a^{2}+c^{2}-2\cdot a \cdot c \cdot \cos B}$

$b = \sqrt{16^{2}+12^{2}-2\cdot (16)\cdot (12) \cdot \cos 63^{\circ}}$

$b \approx 15.022$

Angle A (Law of Cosine)

$\cos A = -\frac{a^{2} - b^{2}-c^{2}}{2\cdot b \cdot c}$

$\cos A = - \frac{16^{2}-15.022^{2}-12^{2}}{2\cdot (15.022)\cdot (12)}$

$\cos A = 0.315$

$A= \cos^{-1} 0.315$

$A \approx 71.639^{\circ}$

Angle C (Sum of internal angles in triangles)

$C = 180^{\circ} - 63^{\circ} - 71.639^{\circ}$

$C = 45.361^{\circ}$

Hence, the right answer is B.

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3 years ago

Need the answers for 8 and 9 ASAP! WILL MARK BRAINLIEST!!

Elza [17]

Answer:

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9) $2^83^4$ =20736

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3 years ago

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Ok... what are you trying to ask

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3 years ago