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3 years ago

Need some help with multiplying algebraic fractions

Mathematics

1 answer:

Nezavi [6.7K]3 years ago

8 0

Answer:

a=10, b=5, c=2, d=12

Step-by-step explanation:

Multiply each variable together

5*2=10

8*3=24

10 $x^{3}$ $y^{2}$ /24x

the coefficients (numbers) can each be divided by 2

5 $x^{3} y^{2}$ /12x

subtract the "x" exponents together

5 $x^{2} y^{2}$ /12

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Which equation represents a proportional relationship? Y=-5(x+1). Y=5x+1. Y=-x. Y=1/5x

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y = kx,

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Answer:

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Step-by-step explanation:

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kkurt [141]

Answer:

$(x- \frac{2}{5})^{2} = x^2 -\frac{4}{5}x + \frac{4}{25}$

Step-by-step explanation:

You have two methods to expand this binomial.

Method 1

If you have the expression:

$(x- \frac{2}{5})^{2}$

You can write the expression it in the following way:

$(x-\frac{2}{5})^{2}=(x-\frac{2}{5})(x-\frac{2}{5})$

Then, apply the distributive property:

$(x-\frac{2}{5})(x-\frac{2}{5}) = x^2 -\frac{2}{5}x -\frac{2}{5}x+ (\frac{2}{5})\frac{2}{5}$

Simplify the expression:

$(x-\frac{2}{5})^2= x^2 -\frac{4}{5}x+ (\frac{4}{25})$

---------------------------------------------------------------------------------------

Method 2

For any expression of the form:

$(a-b)^2$

Its expanded form will be:

$(a-b)^2= a^2 -2ab + b^2$

$a = x$

$b =\frac{2}{5}$

$(x- \frac{2}{5})^{2} = x^2 - 2x\frac{2}{5} + (\frac{2}{5})^2$

$(x- \frac{2}{5})^{2} = x^2 -\frac{4}{5}x + \frac{4}{25}$

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