I=PRT
I=Interest
P=principal
R=rate in decimal
T=time in years
1year=12months
72months/12months=6 years
t=6
given
I=8925
P=35000
R=r
T=6
8925=35000*r*6
8925=210000*r
divide both sides by 210000
0.0425=r
the interest rate is 4.25%
8 cm and 9 cm is the correct answer
1-1/6*3/2
multiply the two fractions
1/6*3/2
Cross out 3 and 6, divide by 3.
1/2 * 1/2
multiply the numerators together
1*1=1
multiply the denominators together
2*2=4
1-1/4
pretend that 1 has a denominator which is 1
1/1-1/4
find the common denominator for 1/1 which is 4
multiply by 4 for 1/1
1*4/1*4=4/4
4/4-1/4
Answer:
3/4
9514 1404 393
Answer:
a) E = 6500 -50d
b) 5000 kWh
c) the excess will last only 130 days, not enough for 5 months
Step-by-step explanation:
<u>Given</u>:
starting excess (E): 6500 kWh
usage: 50 kWh/day (d)
<u>Find</u>:
a) E(d)
b) E(30)
c) E(150)
<u>Solution</u>:
a) The exces is linearly decreasing with the number of days, so we have ...
E(d) = 6500 -50d
__
b) After 30 days, the excess remaining is ...
E(30) = 6500 -50(30) = 5000 . . . . kWh after 30 days
__
c) After 150 days, the excess remaining would be ...
E(150) = 6500 -50(150) = 6500 -7500 = -1000 . . . . 150 days is beyond the capacity of the system
The supply is not enough to last for 5 months.
Hello! here are the basic rules that you need to know to solve these problems:
a diameter is 2 × the radius
the circumference rule is 2×π×radius
I will solve the first question to show how to format.
1: 5/2=2.5
2×2.5×π=5×π=15.7
