Let the required equation be y = mx + c; where y = 1, m = f'(0), x = 0
f(a) = sec(a)
f'(a) = sec(a)tan(a)
f'(0) = sec(0)tan(0) = 0
y = mx + c
1 = 0(0) + c
c = 1
Therefore, required equation is
y = 1.
for this question you would need to utilize ratios to find the side lengths. For example, set up a ratio between the big triangle with the small triangle to find a side length
Answer: y= -4cos (pi/4x)-3
Step-by-step explanation:
