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1 year ago

Which equation describes how the parent function, y = x3, is vertically stretched by a factor of 4?

Mathematics

1 answer:

wlad13 [49]1 year ago

8 0

Answer: $y=4x^3$

Step-by-step explanation:

See attached image.

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Gil bought 2 packs of pencils there were 10 pencils in each pack how many pencils did Gil buy

kupik [55]

Answer:

gill bought 20 pencils

Step-by-step explanation:

10 pencils in each pack × 2 packs = 20 pencils in total

3 0

2 years ago

What is the diameter of a circle with area of 113.04 square cm. use 3.14? pls fast

galina1969 [7]

Answer:

diameter of a circle = 12cm

Step-by-step explanation:

Area of a circle = πr²

113.04 cm² = πr²

First, search for radius (r) :-

r = √(113.04/π)

r = 6 cm

As diameter is equals to 2×radius

The diameter of a circle = 2 × 6cm

Final answer = 12 cm

3 0

2 years ago

Read 2 more answers

Find the slope of the line shown on the graph to the right.Select the correct choice below and fill in any answer boxes within y

klasskru [66]

We can see that the line is horizontal so its slope is 0.

5 0

7 months ago

Can someone help out?

Zina [86]

Answer: x is less than or equal to 35.

Step-by-step explanation:

8 0

3 years ago

Suppose you have a light bulb that emits 50 watts of visible light. (Note: This is not the case for a standard 50-watt light bul

natali 33 [55]

Answer:

0.049168726 light-years

Step-by-step explanation:

The apparent brightness of a star is

$\bf B=\displaystyle\frac{L}{4\pi d^2}$

where

L = luminosity of the star (related to the Sun)

d = distance in ly (light-years)

The luminosity of Alpha Centauri A is 1.519 and its distance is 4.37 ly.

Hence the apparent brightness of Alpha Centauri A is

$\bf B=\displaystyle\frac{1.519}{4\pi (4.37)^2}=0.006329728$

According to the inverse square law for light intensity

$\bf \displaystyle\frac{I_1}{I_2}=\displaystyle\frac{d_2^2}{d_1^2}$

where

$\bf I_1=$ light intensity at distance $\bf d_1$

$\bf I_2=$ light intensity at distance $\bf d_2$

Let $\bf d_2$ be the distance we would have to place the 50-watt bulb, then replacing in the formula

$\bf \displaystyle\frac{0.006329728}{50}=\displaystyle\frac{d_2^2}{(4.37)^2}\Rightarrow\\\\\Rightarrow d_2^2=\displaystyle\frac{0.006329728*(4.37)^2}{50}\Rightarrow d_2^2=0.002417564\Rightarrow\\\\\Rightarrow d_2=\sqrt{0.002417564}=\boxed{0.049168726\;ly}$

Remark: It is worth noticing that Alpha Centauri A, though is the nearest star to the Sun, is not visible to the naked eye.

7 0

3 years ago