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blondinia [14]
3 years ago
9

Explain how 2 ones is the same as 20 tenths

Mathematics
1 answer:
Vladimir [108]3 years ago
5 0
The tenths place can only go up to nine because when you have 10 it then move on to the ones place .              .9 plus .1 =1.0
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Fill in the next entry in the pattern<br> 81, 27, 9, 3,
Dominik [7]
The answer to your problem is 1
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4 years ago
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The area of sandbox in park is represented by 2X^2-5x-3 find the dimensions of the sandbox in terms of
lora16 [44]

Answer:

The dimension of the sandbox is (2x+1) by (x - 3)

Step-by-step explanation:

It seems the complete question will be:

The area of sandbox in park is represented by 2X^2-5x-3 find the dimensions of the sandbox in terms of x.

Step-by-step explanation:

From the question, the given expression is 2X^2-5x-3. This can be rewritten as

2x^{2} -5x-3

If the area of the sandbox in park is represented by this expression, then the dimensions of the sandbox will be the product of the factors. To determine the factors, we will factorize the given quadratic expression.

Factorizing the expression 2x^{2} -5x-3, we get

2x^{2} -6x+x-3

2x(x-3)+1(x-3)

(2x+1)(x-3)

Hence, the dimension of the sandbox is (2x+1) by (x - 3)

6 0
3 years ago
Choose the point-slope form of the equation below that
PilotLPTM [1.2K]

Answer:

A) y-4=-1/2(x+6)

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(0-4)/(2-(-6))

m=-4/(2+6)

m=-4/8

simplify

m=-1/2

y-y1=m(x-x1)

y-4=-1/2(x-(-6))

y-4=-1/2(x+6)

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2 years ago
To find the value of 6 divided by 2/3 Elena began by drawing her diagram in the same way she did 6 divided by 1/3. Use her diagr
Rom4ik [11]
I think the corcorrect answer is c
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3 years ago
PLS HELP!! AND HURRY!! Find an expression for the nth term ( tn ) in each of the following sequences:
fiasKO [112]

If the pattern continues, so that each term is separated by a distance of 3, then the sequence is given by the recursive rule

\begin{cases}a_1=1\\a_n=a_{n-1}+3&\text{for }n>1\end{cases}

From this definition, we can write a_n in terms of a_1:

a_2=a_1+3

a_3=a_2+3=(a_1+3)+3=a_1+2\cdot3

a_4=a_3+3=(a_1+2\cdot3)+3=a_1+3\cdot3

a_5=a_4+3=(a_1+3\cdot3)+3=a_1+4\cdot3

and so on, up to

a_n=a_1+(n-1)\cdot3

(notice how the subscript on <em>a</em> and coefficient on 3 add up to <em>n</em>)

or

a_n=1+3(n-1)=3n-2

6 0
3 years ago
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