We are asked to express cos^ 3 x in terms of powers of trigonometric functions not greater than 1
cos ^ 3 x is equal to cos x * cos^2 x.
<span>cos^2 x = 1 - sin^2 x.
</span>sin^2 x = (1 - cos 2x) /2
the answer is cos ^ 3 x = cos x * (1 - <span> (1 - cos 2x) /2 )</span>
Given:
The points are (-3, 2) and (2, -13).
To find:
Slope-intercept form of the equation.
Solution:
Here .
Slope of the line:
m = -3
Using point-slope formula:
Add 2 on both sides.
Slope-intercept form of the equation is y = -3x - 7.
A. is the answer i’m pretty sure