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2 years ago

PLEASE HELP ME

Mathematics

2 answers:

poizon [28]2 years ago

8 0

Answer is part 2 hope this helps have a great day

irina [24]2 years ago

7 0

Answer: pt 2 HOPE THIS HELPS!

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Toms banks baleances at the end of the months 1,2,3 are 1600 ,1664,1730.56 what will toms balance be at the end of month 5

Sergeeva-Olga [200]

Answer:

Tom's balance at the end of month 5 = 1,871.77

Step-by-step explanation:

a = 1600

ar = 1664

ar² = 1730.56

common ratio, r = ar/a

= 1664/1600

= 1.04

r = 1.04

what will toms balance be at the end of month 5

Month 5 = ar⁴

= 1600 * 1.04⁴

= 1600 * 1.16985856

= 1,871.773696

Approximately 1,871.77

Tom's balance at the end of month 5 = 1,871.77

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2 years ago

Solve the system of linear equations for x and y.(cos θ)x + (sin θ)y=1(−sin θ)x + (cos θ)y = 0x=y=

lys-0071 [83]

Answer:

$\bold{x =cos\theta}\\\bold{y=sin\theta}$

Step-by-step explanation:

The given system of linear equations is:

$(cos\theta)x+(sin\theta)y=1\\(-sin\theta)x+(cos\theta)y=0$

We have to solve the equations for the values of $x, y$ .

Let us use elimination method in which we eliminate one of the variables from the two variables.

For this, let us multiply the first equation by $sin\theta$ and second equation by $cos\theta$

Now, the equations become:

$(cos\theta.sin\theta)x+(sin\theta.sin\theta)y=sin\theta\\\Rightarrow (cos\theta.sin\theta)x+(sin^2\theta)y=sin\theta ....... (1)\\\\(-sin\theta.cos\theta)x+(cos\theta.cos\theta)y=0\\\Rightarrow (-sin\theta.cos\theta)x+(cos^2\theta)y=0 ..... (2)$

Now, let us add (1) and (2):

$(sin^2\theta)y+(cos^2\theta)y=sin\theta\\\Rightarrow (sin^2\theta+cos^2\theta)y=sin\theta\\\Rightarrow (1)y=sin\theta\\\Rightarrow y = sin\theta$

Using the equation:

$(-sin\theta)x+(cos\theta)y=0$

Putting value of $y$ :

$\Rightarrow (-sin\theta)x+(cos\theta)sin\theta=0\\\Rightarrow (sin\theta)x=(cos\theta)sin\theta\\\Rightarrow x = cos\theta$

So, the answer to the system of linear equations is:

$\bold{x =cos\theta}\\\bold{y=sin\theta}$

7 0

2 years ago