Answer: 0.0475
Step-by-step explanation:
Let x = random variable that represents the number of a particular type of bacteria in samples of 1 milliliter (ml) of drinking water, such that X is normally distributed.
Given: 
The probability that a given 1-ml will contain more than 100 bacteria will be:
![P(X>100)=P(\dfrac{X-\mu}{\sigma}>\dfrac{100-85}{9})\\\\=P(Z>1.67)\ \ \ \ [Z=\dfrac{X-\mu}{\sigma}]\\\\=1-P(Zz)=1-P(Z](https://tex.z-dn.net/?f=P%28X%3E100%29%3DP%28%5Cdfrac%7BX-%5Cmu%7D%7B%5Csigma%7D%3E%5Cdfrac%7B100-85%7D%7B9%7D%29%5C%5C%5C%5C%3DP%28Z%3E1.67%29%5C%20%5C%20%5C%20%5C%20%5BZ%3D%5Cdfrac%7BX-%5Cmu%7D%7B%5Csigma%7D%5D%5C%5C%5C%5C%3D1-P%28Z%3C1.67%29%5C%20%5C%20%5C%20%5BP%28Z%3Ez%29%3D1-P%28Z%3Cz%29%5D%5C%5C%5C%5C%3D1-%200.9525%3D0.0475)
∴The probability that a given 1-ml will contain more than 100 bacteria
0.0475.
Answer:
-4, 19
Step-by-step explanation:
The answer is 12 I promise
Y=mx+b change the equation to solve for m instead. first subtract b on both sides
y-b=mx then divide both sides by x
(y-b)/x=m
m=(y-b)/x
9514 1404 393
Answer:
A) 5x+12 = -12x-12
D) 5x+12 = -5x-12
Step-by-step explanation:
If you subtract the right side expression from both sides, you will get an equation with something equal to zero. If the 'something' has a variable in it, there is exactly one solution.
A: (5x+12) -(-12x-12) = 17x+24 = 0 . . . one solution
B: (5x+12) -(5x-5) = 17 = 0 . . . . no solutions
C: (5x+12)-(5x+12) = 0 = 0 . . . . infinite solutions
D: (5x+12) -(-5x-12) = 10x +24 = 0 . . . one solution
