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Westkost [7]
4 years ago
10

Use the divergence theorem to evaluate the integral i = z z ∂w f · ds when f(x, y, z) = y i − 4yz j + 3z 2 k and ∂w is the bound

ary of the solid w enclosed by the upper half of the sphere
Mathematics
1 answer:
andre [41]4 years ago
6 0

\vec f(x,y,z)=y\,\vec\imath-4yz\,\vec\jmath+3z^2\,\vec k

\implies\nabla\cdot\vec f(x,y,z)=0-4z+6z=2z

By the divergence theorem,

\displaystyle\iint_{\partial W}\vec f\cdot\mathrm d\vec S=\iiint_W2z\,\mathrm dV

I'll assume a sphere of radius r centered at the origin, and that W is bounded below by the plane z=0. Convert to spherical coordinates, taking

x=\rho\cos\theta\sin\varphi

y=\rho\sin\theta\sin\varphi

z=\rho\cos\varphi

Then

\displaystyle\iiint_W2z\,\mathrm dV=\int_0^{\pi/2}\int_0^{2\pi}\int_0^r2\rho^3\cos\varphi\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi=\pi r^4

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