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2 years ago

V = 1/3× B×h

Mathematics

2 answers:

Fiesta28 [93]2 years ago

5 0

Answer:

letter "B"

Step-by-step explanation:

V = (1/3)Bh

solve for B: 3V = Bh

B = 3V/h

dybincka [34]2 years ago

5 0

Answer:

It's "A" (B= 3 V/h)

Step-by-step explanation:

I know this because I got a math question once, and it was to find the solve for v in this question: b= 3 v/h. So when I solved the problem, it was basically your question.

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Answer:

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Step-by-step explanation:

3x+6y=24

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2 years ago

The two interior opposite Angel's of a triangle are 60° and 80°. Find the measure of the exterior angle.

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2 years ago

Show that if X is a geometric random variable with parameter p, then

Lubov Fominskaja [6]

Answer:

$\sum_{k=1}^{\infty} \frac{p(1-p)^{k-1}}{k}=-\frac{p ln p}{1-p}$

Step-by-step explanation:

The geometric distribution represents "the number of failures before you get a success in a series of Bernoulli trials. This discrete probability distribution is represented by the probability density function:"

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In order to find the expected value E(1/X) we need to find this sum:

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Lets consider the following series:

$\sum_{k=1}^{\infty} b^{k-1}$

And let's assume that this series is a power series with b a number between (0,1). If we apply integration of this series we have this:

$\int_{0}^b \sum_{k=1}^{\infty} r^{k-1}=\sum_{k=1}^{\infty} \int_{0}^b r^{k-1} dt=\sum_{k=1}^{\infty} \frac{b^k}{k}$ (a)

On the last step we assume that $0\leq r\leq b$ and $\sum_{k=1}^{\infty} r^{k-1}=\frac{1}{1-r}$ , then the integral on the left part of equation (a) would be 1. And we have:

$\int_{0}^b \frac{1}{1-r}dr=-ln(1-b)$

And for the next step we have:

$\sum_{k=1}^{\infty} \frac{b^{k-1}}{k}=\frac{1}{b}\sum_{k=1}^{\infty}\frac{b^k}{k}=-\frac{ln(1-b)}{b}$

And with this we have the requiered proof.

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$\sum_{k=1}^{\infty} \frac{p(1-p)^{k-1}}{k}=-\frac{p ln p}{1-p}$

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