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raketka [301]
3 years ago
10

I got shocked when I entered my school bus last Thursday. It was full of lizards and snakes. There were 214 lizards and snakes o

n the bus. There were 36 fewer lizards than snakes. There were 31 more female snakes than male snakes. How many female snakes were on the bus?
Mathematics
2 answers:
s344n2d4d5 [400]3 years ago
7 0

Answer:

x=lizards y=snakes

x+36=y x+y=214

x + x +36=214

2x=214-36

2x/2=178/2

x=89lizards y=89+36=125snakes

Step-by-step explanation:

f= female sankes m=male snakes

m+31=f

m+f=125

m+m+31=125

2m=125-31

2m/2=94/2

m=47 male snakes

f=47+31=78female snakes

Debora [2.8K]3 years ago
3 0

Answer:

There were

47 Male snakes and

<u>78 Female snakes</u>

Step-by-step explanation:

Hope this helps!

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Answer: B) (x-1)2+(y+1)2= 25 radius = 5 miles

Step-by-step explanation:

In order to get this answer you see that you are adding a negative to x in the first part then multiplying it by 2. Second, you add y+1 then multiplying it by 2. You get the radius of 25 which equals 5 miles. Look at the graph to also check your answers to the problem.

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4 years ago
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AM is a median in △ABC (M∈ BC ). A line drawn through point M intersects AB at its midpoint P. Find areas of △APC and △PMC, if A
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Answer:

The area of APC is 70m². The area of triangle PMC is 35m².

Step-by-step explanation:

Let the area of triangle ABC be x.

It is given that AM is median, it means AM divides the area of triangle in two equal parts.

\text{Area of }\triangle ACM=\text{Area of }\triangle ABM=\frac{x}{2}    .....(1)

The point P is the midpoint of AB, therefore the area of APC and BPC are equal.

\text{Area of }\triangle APC=\text{Area of }\triangle BPC=\frac{x}{2}          ......(2)

The point P is midpoint of AB therefore the line PM divide the area of triangle ABM in two equal parts. The area of triangle APM and BPM are equal.

\text{Area of }\triangle APM=\text{Area of }\triangle BPM=\frac{x}{4}        .....(3)

The area of triangle APM is 35m².

\text{Area of }\triangle APM=\frac{x}{4}

35=\frac{x}{4}

x=140

Therefore the area of triangle ABC is 140m².

Using equation (2).

\text{Area of }\triangle APC=\frac{x}{2}

\text{Area of }\triangle APC=\frac{140}{2}

\text{Area of }\triangle APC=70

Therefore the area of triangle APC is 70m².

Using equation (3), we can say that the area of triangle BPM is 35m² and by using equation (2), we can say that the area of triangle BPC is 70m².

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70=35+\triangle PMC

35=\triangle PMC

Therefore the area of triangle PMC is 35m².

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4 years ago
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Hey there!

If these hexagons are congruent, then each angle is congruent to the one that is in the same position as it is. In this case, I and V are congruent because they are both last. K and U are congruent because they are both second to last.

While looking over the answer options, you should be able to see that Angle J and Angle S is the only answer with angles that match up, because they are both the first angle in the set.

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