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3 years ago

Pls help i dont understand this!!!

Mathematics

1 answer:

scoundrel [369]3 years ago

7 0

Answer:

I guess x =4 and y =2

I hope it helps

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As an estimation we are told £3 is €4.

agasfer [191]

Answer:

Step-by-step explanation:

7 0

2 years ago

Elise walks diagonally from one corner of a square plaza to another. Each side of the plaza is 505050 meters.

Dennis_Churaev [7]

Answer= 70.7 meters.

Step-by-step explanation:

We have been given that Elise walks diagonally from one corner of a square plaza to another. Each side of the plaza is 50 meters.

Since we know that diagonal of a square is product of side length of square and . So we will find diagonal of our given square plaza by multiplying 50 by .

Therefore, diagonal distance across the plaza is 70.7 meters.

3 0

3 years ago

-0.2(-67+22)=2(7n 3)-8n =?

dangina [55]

70.6 what i got was 70.6753275399

4 0

3 years ago

Rewrite y^2(9y^2+4y-9) in standard form

Margaret [11]

Y²(9y² + 4y - 9)

Simplify.

(y² · 9y²) + (y² · 4y) + (y² · -9)

Simplify.

9y⁴ + 4y³ - 9y²

~Hope I helped!~

8 0

3 years ago

Let R be the relation on the set of ordered pairs of positive integers such that ((a, b), (c, d)) ∈ R if and only if ad = bc. Ar

Veseljchak [2.6K]

Answer:

The given relation R is equivalence relation.

Step-by-step explanation:

Given that:

$((a, b), (c, d))\in R$

Where $R$ is the relation on the set of ordered pairs of positive integers.

To prove, a relation R to be equivalence relation we need to prove that the relation is reflexive, symmetric and transitive.

1. First of all, let us check reflexive property:

Reflexive property means:

$\forall a \in A \Rightarrow (a,a) \in R$

Here we need to prove:

$\forall (a, b) \in A \Rightarrow ((a,b), (a,b)) \in R$

As per the given relation:

$((a,b), (a,b) ) \Rightarrow ab =ab$ which is true.

$\therefore$ R is reflexive.

2. Now, let us check symmetric property:

Symmetric property means:

$\forall \{a,b\} \in A\ if\ (a,b) \in R \Rightarrow (b,a) \in R$

Here we need to prove:

$\forall {(a, b),(c,d)} \in A \ if\ ((a,b),(c,d)) \in R \Rightarrow ((c,d),(a,b)) \in R$

As per the given relation:

$((a,b),(c,d)) \in R$ means $ad = bc$

$((c,d),(a,b)) \in R$ means $cb = da\ or\ ad =bc$

Hence true.

$\therefore$ R is symmetric.

3. R to be transitive, we need to prove:

$if ((a,b),(c,d)),((c,d),(e,f)) \in R \Rightarrow ((a,b),(e,f)) \in R$

$((a,b),(c,d)) \in R$ means $ad = cb$ .... (1)

$((c,d), (e,f)) \in R$ means $fc = ed$ ...... (2)

To prove:

To be $((a,b), (e,f)) \in R$ we need to prove: $fa = be$

Multiply (1) with (2):

$adcf = bcde\\\Rightarrow fa = be$

So, R is transitive as well.

Hence proved that R is an equivalence relation.

8 0

3 years ago