We have the rational expression
; to simplify it, we are going to try to find a common factor in the numerator, and, if we are luckily, that common factor will get rid of the denominator
.
Notice that in the denominator all the numbers are divisible by two, so 2 is part of our common factor; also, all the terms have the variable
, and the least exponent of that variable is 1, so
will be the other part of our common factor. Lets put the two parts of our common factor together to get
.
Now that we have our common factor, we can rewrite our numerator as follows:
We are luckily, we have
in both numerator and denominator, so we can cancel those out:
We can conclude that the simplified version of our rational function is
.
Answer:
thanks I guess for the points
Step-by-step explanation:
Answer:
its obviously the property of zero as an exponent
Step-by-step explanation:
2.5 is the mean of this distribution.
What is the distribution's mean?
- The expected value, commonly known as the mean of a statistical distribution with a continuous random variable, is calculated by integrating the product of the variable's probability as described by the distribution.
- The lowercase Greek letter mu () stands for the expected value. A probability of 50% equals zero standard deviations, and the mean is in the middle of the normal distribution.
Given: p = 0.05 and n= 50
Mean of the binomial distribution = n×p = 50 × 0.05 = 2.5
Therefore, option a is the correct answer. Other options are incorrect because these are irrelevant.
Learn more about binomial distribution
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THE ANSWER IS A:
This is the function:
f(x)=|42.67-x|.
42.670 -.002 =42.668
42.668 mm to 42.670
Explanation:
Production will be stopped if the difference in diameter is greater than 0.002 mm.
This difference can mean that the golf ball has a diameter more than 0.002 larger than 42.67 mm, or a diameter more than 0.002 smaller than 42.67. This is the reason for using an absolute value function.
Absolute value represents the distance a number is from 0. For this function, we would want only the values where the function is less than 0.002.