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steposvetlana [31]
2 years ago
14

Remi is building a triangular wooden shelving unit. The base measures 30 cm and the slant sides measure 18 cm and 24 cm. He want

s a horizontal shelf halfway between the bas and the top. What length of wood should he cut for the shelf?

Mathematics
1 answer:
tresset_1 [31]2 years ago
5 0

Answer:

Remi needs 15 cm of wood to be cut for the shelf.

Step-by-step explanation:

We have drawn the triangle for your reference.

Now Given:

Base measure (BC) =30 cm

Slant height (AB) = 24 cm

Slant height (AC) = 18 cm

Also Given horizontal shelf halfway between the base and the top.

In the triangle drawn horizontal shelf is denoted by DE.

We need to find the measure of DE.

Now we know that horizontal shelf halfway between the base and the top.

Hence by Midpoint theorem which states that;

"The segment joining two sides of a triangle at the midpoints of those sides is parallel to the third side and is half the length of the third side."

DE=\frac{1}{2}\times BC

Substituting the value we get;

DE = \frac{1}{2}\times 30 =15\ cm

Hence Remi needs 15 cm of wood to be cut for the shelf.

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The longest piece of wood that could fit in your trunk to build a gate for the backyard is 60.65 inches.

<h3>How to measure diagonal of the cuboid?</h3>

The length of the diagonal of the cuboid is found out using the following formula.

D=\sqrt{l^2+b^2+h^2}

Here, (l) is the length of the cuboid, (w) is the width, and (h) is the height of the cuboid.

The wood has to buy to build a gate for backyard. The car trunk has the following dimensions (47 inches by 33 inches by 19.5 inches). Here, we have,

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The longest piece of wood which fits is equal to the length of diagonal of cuboid. Put the values in the formula,

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brainly.com/question/22694657

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