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choli [55]
3 years ago
7

Could you anwser this for me​

Mathematics
2 answers:
anastassius [24]3 years ago
4 0
I also got D as the answer

IgorLugansk [536]3 years ago
3 0

Answer:

last answer

Step-by-step explanation:

I factored it, but I might have done it wrong.

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2. What is the y-intercept of this graph?<br> O A. 1<br> O B.-2<br> O C. 2<br> O D.-4
MAVERICK [17]

Answer:

1

Step-by-step explanation:

Because it is where the like crosses with the y axis

3 0
3 years ago
Read 2 more answers
When solving an equation like x3 = 64, why does our solution not include the negative cube root?
MAVERICK [17]
So I’m only answering so I can ask you a question
4 0
2 years ago
Read 2 more answers
A lake contains 4 distinct types of fish. Suppose that each fish caught is equally likely to be any one of these types. Let Y de
gregori [183]

a= μ-3.16*σ , b= μ+3.16*σ if each fish caught is equally likely to be any one of these 4 distinct types.

<h3>What is meant by Chebyshev inequality?</h3>

Chebyshev's inequality is a probability theory that ensures that, over a vast range of probability distributions, no more than a particular proportion of values would be present within a selected limits or range as from mean. In other words, only a certain fish caught will be discovered within a given range of the distribution's mean.

The formula for which no more than a particular number of values can exceed is 1/K2; in other words, 1/K2 of a distribution's values can be more than or equal to K standard deviations away from the distribution's mean. Furthermore, it asserts that 1-(1/K2) of a distribution's values must be within, but not include, K standard deviations of the distribution's mean.

How to solve?

from Chebyshev's inequality for Y

P(| Y - μ|≤ k*σ ) ≥ 1-1/k²

where

Y =  the number of fish that need be caught to obtain at least one of each type

μ = expected value of Y

σ = standard deviation of Y

P(| Y - μ|≤ k*σ ) = probability that Y is within k standard deviations from the mean

k= parameter

thus for

P(| Y - μ|≤ k*σ ) ≥ 1-1/k²

P{a≤Y≤b} ≥ 0.90 →  1-1/k² = 0.90 → k = 3.16

then

P(μ-k*σ≤ Y ≤ μ+k*σ ) ≥ 0.90

using one-sided Chebyshev inequality (Cantelli's inequality)

P(Y- μ≥ λ) ≥ 1- σ²/(σ²+λ²)

P{Y≥b} ≥ 0.90  →  1- σ²/(σ²+λ²)=  1- 1/(1+(λ/σ)²)=0.90 → 3= λ/σ → λ= 3*σ

then for

P(Y≥ μ+3*σ ) ≥ 0.90

In order to learn more about Chebyshev inequality, visit:

brainly.com/question/24971067

#SPJ4

4 0
1 year ago
Which of the following is a solution of x-6&lt;6 AND x+4&gt;-1..
alina1380 [7]

Answer:

2

Step-by-step explanation:

let me know if you need explanation

8 0
2 years ago
A pet supply chain called Pet City has 5 hamsters and 10 gerbils for sale at its Lanberry location. At its Milford location, the
Vlad1618 [11]

Answer:

Milford location has a higher ratio of hamsters to gerbils.

Step-by-step explanation:

Given:

A pet supply chain called Pet City has 5 hamsters and 10 gerbils for sale at its Lanberry location.

At its Milford location, there are 13 hamsters and 16 gerbils.

Now, to find the location who has a higher ratio of hamsters to gerbils.

Ratio of hamsters to gerbils at Lanberry location = 5:10.

=\frac{5}{10}=0.50

                                                                         

Ratio of hamsters to gerbils at Milford location= 13:16.

=\frac{13}{16} =0.8125

                                                       

<em>So, 0.8125 > 0.50.</em>

<em>Thus, </em><u><em>13:16 > 5:10.</em></u><em> </em>

Therefore, Milford location has a higher ratio of hamsters to gerbils.

4 0
3 years ago
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