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4 years ago

How to solve this equation

Mathematics

2 answers:

ser-zykov [4K]4 years ago

8 0

What I got was twelve

r-ruslan [8.4K]4 years ago

6 0

0=-12
It's no solution!

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Ashton is saving money for a new bike. He needs 120$ But only has saved 60% so far. How much more money does he need to buy the

kherson [118]

Answer:

$48

Step-by-step explanation:

Ashton is saving money for a new bike. He needs 120$ But only has saved 60% so far. How much more money does he need to buy the scooter

Ashton needs money for new bike=120$

savings of ashton is 60 % of his bike cost

hence 60% of 120 dollar will be

His saving=(60/100)*120=7200/100=72$

remaining cost will be obtained by subtracting saved money from total cost

total cost=120 dollar

saved money=72dollar

hence

Remaining more money he needed is =120-72=48$

7 0

3 years ago

What is question number 21?

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I tried working it out but I am not sure

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3 years ago

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Rzqust [24]

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3 years ago

Graph the relation {(5, 0), (0, 5), (5, 1), (1, 5)}. Is it a function? Why or why not?

MissTica

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4 years ago

A circular pond 24 yd in

Schach [20]

Answer:

The walk will cost $8164.

Step-by-step explanation:

Given:

Diameter of the circular pond (D) = 24 yd

Width of the gravel path (x) = 2 yd

Cost per yard of the path = $50

Now, radius of the circular pond is half of the diameter and is given as:

$Radius,R=\frac{D}{2}=\frac{24}{2}=12\ yd$

Now, area of the pond is given as:

$A_{pond}=\pi R^2=3.14\times (12)^2=3.14\times 144=452.16\ yd^2$

Area of the complete path including the pond area is given as:

$A_{outer}=\pi(R+x)^2=3.14\times(12+2)^2=3.14\times196=615.44\ yd^2$

Now, area of the gravel path can be obtained by subtracting the pond area from the total outer area. This gives,

$A_{path}=A_{outer}-A_{pond}\\\\A_{path}=615.44-452.16=163.28\ yd^2$

Now, using unitary method,

Cost of 1 square yard of path = $50

∴ Cost of 163.28 square yard of path = 50 × 163.28 = $8164

Hence, the walk will cost $8164.

5 0

4 years ago

Read 2 more answers