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3 years ago

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Wayne needs to drive 470 miles to reach Milwaukee. Suppose he drives at a constant speed of 50 miles per hour. Which function re

presents Wayne’s distance i
n miles from Milwaukee in terms of the number of hours he drives?
Answer choices:
A y = 420x
B y = 470 + 50x
C y = 50 - 470x
D y = 50 + 470x
E y = 470 - 50x

1 answer:

Savatey [412]3 years ago

5 0

B: Because your slope is 50 because it says "per hour" so this leaves out answers A,C, and D. Now you only answers B and E. E is wrong because its a negitve slope and there's nothing in this problem that makes it a negative, so your answer is B

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Answer:

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Step-by-step explanation:

There are two ways we can solve this equation.

<h2>A) Using the formula provided</h2>

The formula provided states that the volume of a cube based on the area of one of it's faces will be $a^{\frac{3}{2}}$ , a the area of one face. Since we know the area of one face, we can substitute that inside the equation.

$100^{\frac{3}{2}}$

It's important to note that when we have a number to a fraction power, it's the same as taking the denominator root of the base to the numerator power.

So - $100^{\frac{3}{2}}$ becomes $\sqrt{100^3}$

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$\sqrt{1000000}=1000$

Therefore, the volume of this cube will be $1000 \ \text{cm}^3$

<h2>B) Using prior knowledge about cubes</h2>

We can additionally use prior knowledge to find the volume of this cube.

We know that the area of a square will be $s^2$ , where s is the length of a side. We also know the formula to find the volume of a cube from it's side length is $s^3$ .

Since we know that one face is 100, we can make an equation - $s^2=100$

$\sqrt{s^2}=\sqrt{100}$
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Hope this helped!

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Step-by-step explanation:

Confidence interval of standard deviation is given as follows;

$\sqrt{\dfrac{\left (n-1 \right )s^{2}}{\chi _{1-\alpha /2}^{}}}< \sigma < \sqrt{\dfrac{\left (n-1 \right )s^{2}}{\chi _{\alpha /2}^{}}}$

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Where:

$\bar x$ = Sample mean

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χ = Chi squared value at the given confidence level

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The sample standard deviation s = $\sqrt{\dfrac{\Sigma (x - \bar x)^2}{n - 1} }$ = 2.854

The test statistic, derived through computation, = ±3.707

Which gives;

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