Answer:
The answer is "
".
Step-by-step explanation:
Therefore in this question the "bh" were the multiplied and these values includes the variable which is solving by the isolating of "b".
Let's Divides the both sides for h.

$1.40 - price from a supplier = 100%
100% + 80% = 180% = 1,8 - the retail price
1,40 * 1,8 = $2,52 - the retail price
100% - 25% = 75% = 0,75 - on sale for 25% off
2,52 * 0,75 = $1,89 - the sale price.
There are 30 days in the month of June. Out of the 30 days, Ava saw birds on 18.
P(bird)=18/30
We can simplify the fraction by dividing both sides by 2.
P(bird)=18/30=9/15
9/15=0.6=60%
Theres a 9/15 or 60% chance that she will see a bird on July 1st.
Answer:
The 95% confidence interval for the true proportion of university students who use laptop in class to take notes is (0.2839, 0.4161).
Step-by-step explanation:
The (1 - <em>α</em>)% confidence interval for population proportion <em>P</em> is:

The information provided is:
<em>x</em> = number of students who responded as"yes" = 70
<em>n</em> = sample size = 200
Confidence level = 95%
The formula to compute the sample proportion is:

The R codes for the construction of the 95% confidence interval is:
> x=70
> n=200
> p=x/n
> p
[1] 0.35
> s=sqrt((p*(1-p))/n)
> s
[1] 0.03372684
> E=qnorm(0.975)*s
> lower=p-E
> upper=p+E
> lower
[1] 0.2838966
> upper
[1] 0.4161034
Thus, the 95% confidence interval for the true proportion of university students who use laptop in class to take notes is (0.2839, 0.4161).
For the first 6 trips she walked 3.2 kilometers and for the next 6 she made another 3.2 which would be 6.4 kilometers for 12 trips now she made 3 more trips which is half of the amount she originally did so it would be half of the distance also so 3.2 divided by 2 is 1.6 kilometers so for the last 3 trips she walked 1.6 kilometers. now add up all the distance she walked so 6.4 kilometers for the 12 trips plus the 1.6 for the other 3 trips is 8 kilometers in total. she walked 8 kilometers after 15 trips.