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Stels [109]
3 years ago
11

Please help I need answers quick! please zoom in!

Mathematics
2 answers:
kolezko [41]3 years ago
3 0

Answer:

yes x=4 is a solution

Step-by-step explanation:

45x = 180

divide each side by 45

45x/45 = 180/45

x = 4

x=4 is a solution

xxMikexx [17]3 years ago
3 0
The correct answer would be : yes
x = 4 is the solution to the equation.

I hope that this helps you !
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50 PTS
liubo4ka [24]

Answer:

The correct option is B.

Step-by-step explanation:

The amount of money, in dollars, in a savings account after x years is given by  M(x) = 10000(1.03)^{x}

This above equation represents that $10000 becomes M(x) after x years at a rate of interest 3% compounded in each year.

Therefore, the value in the expression 1.03 represents that there is a 3 percent increase in the savings account each year.

So, the correct option is B. (Answer)

8 0
4 years ago
What is 1,773 divide by 3 be honest
-BARSIC- [3]

what is 1,773 divide by 3 be honest

Answer:

<h2>591</h2>

Step-by-step explanation:

Hope it helps:)

#CarryOnLearning

3 0
3 years ago
Read 2 more answers
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andreev551 [17]
The function represented in the table is linear.
8 0
3 years ago
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Enter an equation that can be used to solve this problem, where x represents the number of hours that Roberto had been traveling
ElenaW [278]
Hey any chance you remember the work answer for the problem? I have the same question also!
3 0
3 years ago
A particle moves on a coordinate line with an acceleration at time t seconds of e^t/2 m/sec^2. At t=0 the particle is at the ori
castortr0y [4]
Hello,

A) a=e^ \frac{t}{2} \\\\&#10;&#10;v(t)=\int\ a\ dt=\int\ e^ \frac{t}{2}\ dt=2*e^ \frac{t}{2}+C\\\\v(0)=-4\\&#10; 2*e^ \frac{0}{2}+C=-4\\&#10; C=-6\\\\&#10;&#10;\boxed{v(t)= 2*e^ \frac{0}{2}-6}\\\\&#10;&#10;&#10;&#10;

B)
2*e^ \frac{t}{2}-6=0\\\\&#10;&#10;e^ \frac{t}{2}=3\\\\&#10;&#10;t=2*ln(3)\approx{2,19722...}\\&#10;&#10;

C)

x(t)=\int_0^6(2*e^ \frac{t}{2}-6})\ dt=\left[4*e^ \frac{t}{2}-6t\right]_0^6\\\\ =e^3-36-4=4e^3-40\approx{40.3421...}\\\\



5 0
3 years ago
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