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Stels [109]
3 years ago
11

Please help I need answers quick! please zoom in!

Mathematics
2 answers:
kolezko [41]3 years ago
3 0

Answer:

yes x=4 is a solution

Step-by-step explanation:

45x = 180

divide each side by 45

45x/45 = 180/45

x = 4

x=4 is a solution

xxMikexx [17]3 years ago
3 0
The correct answer would be : yes
x = 4 is the solution to the equation.

I hope that this helps you !
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Park two has 12 more benches than Park one. If 2 benches were transferred from Park two to Park one, then Park two would have 2
marta [7]

Answer:

There were 6 benches in park 1 and 18 benches in park 2.

Step-by-step explanation:

Let x be the no of benches in Park 1 and y in park 2.

Given that there are 12 more benches in park 2 than 1

Writing this in equation form, we have y = x+12 ... i

Next is if 2 benches were transferred from park 2 to park 1, then we have

x+2 in park 1 and y-2 in park 2.

Given that y-2 = twice that of x+2

Or y-2 = 2x+4 ... ii

Rewrite by adding 2 to both sides of equation ii.

y = 2x+6 ... iii

i-iii gives 0 = -x+6

Or x =6

Substitute in i, to have y = 6+12 = 18

Verify:

Original benches 6 and 18.

18 = 6+12 hence I condition is satisfied

18-2 = 2(6+2)

II is also satisfied.

6 0
3 years ago
Read 2 more answers
Find the exact value of cos(sin^-1(-5/13))
son4ous [18]

bearing in mind that the hypotenuse is never negative, since it's just a distance unit, so if an angle has a sine ratio of -(5/13) the negative must be the numerator, namely -5/13.

\bf cos\left[ sin^{-1}\left( -\cfrac{5}{13} \right) \right] \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{then we can say that}~\hfill }{sin^{-1}\left( -\cfrac{5}{13} \right)\implies \theta }\qquad \qquad \stackrel{\textit{therefore then}~\hfill }{sin(\theta )=\cfrac{\stackrel{opposite}{-5}}{\stackrel{hypotenuse}{13}}}\impliedby \textit{let's find the \underline{adjacent}}

\bf \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{13^2-(-5)^2}=a\implies \pm\sqrt{144}=a\implies \pm 12=a \\\\[-0.35em] ~\dotfill\\\\ cos\left[ sin^{-1}\left( -\cfrac{5}{13} \right) \right]\implies cos(\theta )=\cfrac{\stackrel{adjacent}{\pm 12}}{13}

le's bear in mind that the sine is negative on both the III and IV Quadrants, so both angles are feasible for this sine and therefore, for the III Quadrant we'd have a negative cosine, and for the IV Quadrant we'd have a positive cosine.

8 0
3 years ago
Solve for (c).<br><br> 12c−4=14c−10<br> c= ?
kozerog [31]

Answer:

c=3

Step-by-step explanation:

do u need the explanation?

7 0
3 years ago
Read 2 more answers
Use complete sentences to describe why √-1≠-√1
Salsk061 [2.6K]

Answer: because √-1 complex number ; and -√1 real number

Step-by-step explanation:

because √-1 complex number ; and -√1 real number or                                         \displaystyle\ (\sqrt{-1})^2 \neq(- \sqrt{1} )^2 \\\\-1\neq 1                                              

7 0
3 years ago
-28-6b=8 I can’t get the answer I need help.
SVETLANKA909090 [29]

Answer:

6

Step-by-step explanation:

-28-6b=8

-6b=36

b=6

5 0
1 year ago
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