Answer:
Types of polygon
Polygons can be regular or irregular. If the angles are all equal and all the sides are equal length it is a regular polygon.
Regular and irregular polygons
Interior angles of polygons
To find the sum of interior angles in a polygon divide the polygon into triangles.
Irregular pentagons
The sum of interior angles in a triangle is 180°. To find the sum of interior angles of a polygon, multiply the number of triangles in the polygon by 180°.
Example
Calculate the sum of interior angles in a pentagon.
A pentagon contains 3 triangles. The sum of the interior angles is:
180 * 3 = 540
The number of triangles in each polygon is two less than the number of sides.
The formula for calculating the sum of interior angles is:
(n - 2) * 180 (where n is the number of sides)
Answer:
Area covered by the fences will be 16.1 unit²
Step-by-step explanation:
Let the first parabola is represented by the function f(x) = 6x²
and second parabola by g(x) = x² + 9
point of intersection of the graphs will be determined when f(x) = g(x)
6x² = x² + 9
5x² = 9
x² = 1.8
x = ± 1.34
Now we will find the area between these curves drawn on the graph.
Area = ![\int_{-1.34}^{1.34}[f(x)-g(x)]dx=\int_{-1.34}^{1.34}[6x^{2}-(x^{2}+9)]dx](https://tex.z-dn.net/?f=%5Cint_%7B-1.34%7D%5E%7B1.34%7D%5Bf%28x%29-g%28x%29%5Ddx%3D%5Cint_%7B-1.34%7D%5E%7B1.34%7D%5B6x%5E%7B2%7D-%28x%5E%7B2%7D%2B9%29%5Ddx)
= 
= ![[\frac{5}{3}x^{3}-9x]_{-1.34}^{1.34}](https://tex.z-dn.net/?f=%5B%5Cfrac%7B5%7D%7B3%7Dx%5E%7B3%7D-9x%5D_%7B-1.34%7D%5E%7B1.34%7D)
= ![[\frac{5}{3}(-1.34)^{3}-9(-1.34)-\frac{5}{3}(1.34)^{3}+9(1.34)]](https://tex.z-dn.net/?f=%5B%5Cfrac%7B5%7D%7B3%7D%28-1.34%29%5E%7B3%7D-9%28-1.34%29-%5Cfrac%7B5%7D%7B3%7D%281.34%29%5E%7B3%7D%2B9%281.34%29%5D)
= ![[-4.01+12.06-4.01+12.06]](https://tex.z-dn.net/?f=%5B-4.01%2B12.06-4.01%2B12.06%5D)
= 16.1 unit²
I think it's 1/4 because -4/1
Answer:
Cost for 68 words = 148 naira
Step-by-step explanation:
Given that:
Cost of first ten words = 32 naira
Cost of additional words = 2 naira per word
Let,
x be the number of additional words.
y be the total cost
y = 2x + 32
We have to find the cost for 68 words.
The cost of first 10 words will be 32 naira.
Additional words = 68 - 10 = 58 words
Putting x = 58 in the equation
y = 2(58) + 32
y = 116 + 32
y = 148
Hence,
Cost for 68 words = 148 naira
Answer:
A)11
Step-by-step explanation:
These are matrices one dimensional with one column and 3 rows each.
-The product of the matrices is obtained by multiplying the correspond values and summing up;
![pq=\left[\begin{array}{ccc}3\\2\\-1\end{array}\right] \times\left[\begin{array}{ccc}5\\-1\\2\end{array}\right] \\\\\\\\=(3\times 5)+(2\times -1)+(-1\times 2)\\\\=15+-2+-2\\\\=11](https://tex.z-dn.net/?f=pq%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%5C%5C2%5C%5C-1%5Cend%7Barray%7D%5Cright%5D%20%5Ctimes%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%5C%5C-1%5C%5C2%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%5C%5C%5C%5C%5C%5C%3D%283%5Ctimes%205%29%2B%282%5Ctimes%20-1%29%2B%28-1%5Ctimes%202%29%5C%5C%5C%5C%3D15%2B-2%2B-2%5C%5C%5C%5C%3D11)
Hence, the product of p and q is 11
