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2 years ago

Can you help I’ll mark brainliest

Mathematics

1 answer:

Marta_Voda [28]2 years ago

6 0

Answer:

$7\sqrt{3}$

Step-by-step explanation:

Since this is a 30-60-90 triangle, we know that the sides have the following characteristic:

The side opposite to 30 degree angle: n

The side opposite to 60 degree angle: $n\sqrt{3}$

The side opposite to 90 degree angle: 2n

Since we know that 7 is opposite to 30-degree, and x is opposite to 60 degree, than we know that x = $7\sqrt{3}$

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What are the steps for long division?

diamong [38]

This is what I learned:

D = Divide
M = Multiply
S = Subtract
B = Bring down
C= Check

D= Dad
M= Mom
S= Sister
B= Brother
C= Cousin

Hope this helped you! :)

8 0

3 years ago

Find the square root by factor 21904

mihalych1998 [28]

$21904|2\\10952|2\\.\ 5476|2\\.\ 2738|2\\.\ 1369|37\\.\ \ \ \ 37|37\\.\ \ \ \ \ \ 1|\\\\21904=2\times2\times2\times2\times37\times37=2^4\times37^2\\\\\sqrt{21904}=\sqrt{2^4\times37^2}=\sqrt{2^4}\times\sqrt{37^2}=2^2\times37=4\times37=148$

$\sqrt{21904}=\sqrt{4\times5476}=2\sqrt{4\times1369}=2\times2\sqrt37\times37}=4\times37=148$

8 0

3 years ago

Read 2 more answers

For the following demand equation compute the elasticity of demand and determine whether the demand is elastic, unitary, or inel

adelina 88 [10]

Answer:

Demand is inelastic at p = 9 and therefore revenue will increase with

an increase in price.

Step-by-step explanation:

Given a demand function that gives q in terms of p, the elasticity of demand is

$E=|\frac{p}{q}\cdot \frac{dq}{dp} |$

If E < 1, we say demand is inelastic. In this case, raising prices increases revenue.
If E > 1, we say demand is elastic. In this case, raising prices decreases revenue.
If E = 1, we say demand is unitary.

We have the following demand equation $D(p)=-\frac{3}{4}p+29$ ; p = 9

Applying the above definition of elasticity of demand we get:

$E(p)=\frac{p}{q}\cdot \frac{dq}{dp}$

where

p = 9
q = $-\frac{3}{4}p+29$
$\frac{dq}{dp}=\frac{d}{dp}(-\frac{3}{4}p+29)$

$\frac{d}{dp}\left(-\frac{3}{4}p+29\right)=-\frac{d}{dp}\left(\frac{3}{4}p\right)+\frac{d}{dp}\left(29\right)\\\\\frac{d}{dp}\left(-\frac{3}{4}p+29\right)=-\frac{3}{4}$

Substituting the values

$E(9)=\frac{9}{-\frac{3}{4}(9)+29}\cdot -\frac{3}{4}\\\\E(9)=\frac{36}{89}\cdot -\frac{3}{4}\\\\E(9)=-\frac{27}{89}\approx -0.30337$

$|E(9)|=|\frac{27}{89}| < 1$

Demand is inelastic at p = 9 and therefore revenue will increase with an increase in price.

6 0

3 years ago

What is the ratio of nickels to quarters in a dollar

Nina [5.8K]

Since the nickles are first and there are (1.00 /.05= 20) 20 nickles in a dollar the first number is 20 then next is quarters and there is (1.00 / .25= 4) 4 quarters in a dollar so the second number is 4 so now u have to simplify if you were told to
the number 20 can be divided by 4 and the answer is 5 the number 4 is next divide by 4 and is 1 so the whole answer is 5 to 1 or 5:1

7 0

2 years ago

Read 2 more answers

A sprinter who weighs 706 N runs the first 5.5 m of a race in 1.6 s, starting from rest and accelerating uniformly. What are the

zhenek [66]

Answer:

(a) Speed = 6.875 m/s

(b) Kinetic Energy = 1.70 kJ

Step-by-step explanation:

Given:

d = 5.5 m

t = 1.6 s

W = 706 N

Part (a)

Using the equation of motion with the assumption of zero initial speed:

$d = \frac{1}{2} ({v-0})t$

$5.5= \frac{1}{2} (1.6v)$

The speed of the sprinter then become:

$v = 6.875 m/s$

Part (b)

Convert the weight of the sprinter to mass:

$m = \frac{w}{g}$

$m = \frac{706}{9.8}$

$m = 72 kg$

KE (Kinetic Energy) can then be calculated as:

$KE = \frac{1}{2} mv^{2}$

$KE = \frac{1}{2} (72)(6.875)^{2}$

$KE = 1701.56 J = 1.70 kJ$

Part (c)

The change of the kinetic energy is equivalent to the work done by the sprinter. The average power P is the rate of the work done and can be calculated as

$P = \frac{KE}{t} \\\$

$P = \frac{1701.56}{1.6}$

$P = 1063.48 W = 1.06 kW$

5 0

3 years ago