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3 years ago

What perfect swuare lies between 120 and 130

Mathematics

1 answer:

Natalka [10]3 years ago

5 0

Answer:

the perfect squares between 120 and 300 are the squares of numbers from 11 to 17. Clearly, these are 7 in number.

Step-by-step explanation:

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I need help on this may you help

HACTEHA [7]

Answer:

should be 63

Step-by-step explanation:

6 0

1 year ago

A bin is constructed from sheet metal with a square base and 4 equal rectangular sides. if the bin is constructed from 48 square

kondaur [170]

This is a problem of maxima and minima using derivative.

In the figure shown below we have the representation of this problem, so we know that the base of this bin is square. We also know that there are four square rectangles sides. This bin is a cube, therefore the volume is:

V = length x width x height

That is:

$V = xxy = x^{2}y$

We also know that the bin is constructed from 48 square feet of sheet metal, so:

Surface area of the square base = $x^{2}$

Surface area of the rectangular sides = $4xy$

Therefore, the total area of the cube is:

$A = 48 ft^{2} = x^{2} + 4xy$

Isolating the variable y in terms of x:

$y = \frac{48- x^{2} }{4x}$

Substituting this value in V:

$V = x^{2}( \frac{48- x^{2} }{x}) = 48x- x^{3}$

Getting the derivative and finding the maxima. This happens when the derivative is equal to zero:

$\frac{dv}{dx} = 48-3x^{2} =0$

Solving for x:

$x = \sqrt{\frac{48}{3}} = \sqrt{16} = 4$

Solving for y:

$y = \frac{48- 4^{2} }{(4)(4)} = 2$

Then, the dimensions of the largest volume of such a bin is:

Length = 4 ft
Width = 4 ft
Height = 2 ft

And its volume is:

$V = (4^{2} )(2) = 32 ft^{3}$

8 0

3 years ago

A business shipped 106 packages one day. Customers are charged 4.50 for each standard delivery and 7.50 for each express deliver

zhuklara [117]

The question is incomplete:

A business shipped 106 packages one day. Customers are charged 4.50 for each standard delivery and 7.50 for each express delivery. Total shipping charges for the day were $600.00. How many of each kind of package were shipped?

Answer:

The business shipped 65 standard delivery packages and 41 express delivery packages.

Step-by-step explanation:

Since the business shipped 106 packages one day you can say that:

x+y=106, where:

x is the number of standard delivery packages

y is the number of express delivery packages

Also, you can say that the result of multiplying the price per each type of package for its amount and adding those would be equal to the total shipping charges for the day, which is:

4.50x+7.50y=600

So, you have the following equations:

x+y=106 (1)

4.50x+7.50y=600 (2)

Now, you can solve for x in (1):

x=106-y (3)

Then, you can replace (3) in (2) and solve for y:

4.50(106-y)+7.50y=600

477-4.50y+7.50y=600

3y=600-477

3y=123

y=123/3

y=41

Finally, you can replace the value of y in (3) to be able to find the value of x:

x=106-41

x=65

According to this, the answer is that the business shipped 65 standard delivery packages and 41 express delivery packages.

3 0

2 years ago

Question 1 (1,2), (-5, –3), (-7,3), (8, 7) represents a function. True False

lara [203]

True (no one input gives two different outputs) good luck!

3 0

2 years ago

Gillam87 and DragonDroppings, what is the square root 144?

VARVARA [1.3K]

Answer:

Sqrt of 144 is 12

Step-by-step explanation:

5 0

3 years ago