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3 years ago

How do u find length of a obtuse angle

Mathematics

2 answers:

Ivenika [448]3 years ago

4 0

Answer:

you can use a protacator to mesurit or find a website that can mesure it for u

Step-by-step explanation:

wolverine [178]3 years ago

3 0

Answer:

An obtuse triangle is a triangle that has a single obtuse angle, which is an angle that measures more than 90 degrees and less than 180 degrees. Obtuse triangles, also referred to as oblique triangles, can be recognized by their having a single significantly larger angle and two smaller angles. Since every triangle has a measurement of 180 degrees, a triangle can only have one obtuse angle. You can calculate an obtuse triangle using the lengths of the triangle's sides.

Square the length of both sides of the triangle that intersect to create the obtuse angle, and add the squares together. For example, if the lengths of the sides measure 3 and 2, then squaring them would result in 9 and 4. Adding the squares together results in 13.

Square the length of the side opposite the obtuse angle. For the example, if the length is 4, then squaring it results in 16.

Step-by-step explanation:

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A box designer has been charged with the task of determining the surface area of various open boxes (no lid) that can be constru

Viktor [21]

Answer:

1) $S = 2\cdot w\cdot l - 8\cdot x^{2}$ , 2) The domain of S is $0 \leq x \leq \frac{\sqrt{w\cdot l}}{2}$ . The range of S is $0 \leq S \leq 2\cdot w \cdot l$ , 3) $S = 176\,in^{2}$ , 4) $x \approx 4.528\,in$ , 5) $S = 164.830\,in^{2}$

Step-by-step explanation:

1) The function of the box is:

$S = 2\cdot (w - 2\cdot x)\cdot x + 2\cdot (l-2\cdot x)\cdot x +(w-2\cdot x)\cdot (l-2\cdot x)$

$S = 2\cdot w\cdot x - 4\cdot x^{2} + 2\cdot l\cdot x - 4\cdot x^{2} + w\cdot l -2\cdot (l + w)\cdot x + l\cdot w$

$S = 2\cdot (w+l)\cdot x - 8\cdpt x^{2} + 2\cdot w \cdot l - 2\cdot (l+w)\cdot x$

$S = 2\cdot w\cdot l - 8\cdot x^{2}$

2) The maximum cutout is:

$2\cdot w \cdot l - 8\cdot x^{2} = 0$

$w\cdot l - 4\cdot x^{2} = 0$

$4\cdot x^{2} = w\cdot l$

$x = \frac{\sqrt{w\cdot l}}{2}$

The domain of S is $0 \leq x \leq \frac{\sqrt{w\cdot l}}{2}$ . The range of S is $0 \leq S \leq 2\cdot w \cdot l$

3) The surface area when a 1'' x 1'' square is cut out is:

$S = 2\cdot (8\,in)\cdot (11.5\,in)-8\cdot (1\,in)^{2}$

$S = 176\,in^{2}$

4) The size is found by solving the following second-order polynomial:

$20\,in^{2} = 2 \cdot (8\,in)\cdot (11.5\,in)-8\cdot x^{2}$

$20\,in^{2} = 184\,in^{2} - 8\cdot x^{2}$

$8\cdot x^{2} - 164\,in^{2} = 0$

$x \approx 4.528\,in$

5) The equation of the box volume is:

$V = (w-2\cdot x)\cdot (l-2\cdot x) \cdot x$

$V = [w\cdot l -2\cdot (w+l)\cdot x + 4\cdot x^{2}]\cdot x$

$V = w\cdot l \cdot x - 2\cdot (w+l)\cdot x^{2} + 4\cdot x^{3}$

$V = (8\,in)\cdot (11.5\,in)\cdot x - 2\cdot (19.5\,in)\cdot x^{2} + 4\cdot x^{3}$

$V = (92\,in^{2})\cdot x - (39\,in)\cdot x^{2} + 4\cdot x^{3}$

The first derivative of the function is:

$V' = 92\,in^{2} - (78\,in)\cdot x + 12\cdot x^{2}$

The critical points are determined by equalizing the derivative to zero:

$12\cdot x^{2}-(78\,in)\cdot x + 92\,in^{2} = 0$

$x_{1} \approx 4.952\,in$

$x_{2}\approx 1.548\,in$

The second derivative is found afterwards:

$V'' = 24\cdot x - 78\,in$

After evaluating each critical point, it follows that $x_{1}$ is an absolute minimum and $x_{2}$ is an absolute maximum. Hence, the value of the cutoff so that volume is maximized is:

$x \approx 1.548\,in$

The surface area of the box is:

$S = 2\cdot (8\,in)\cdot (11.5\,in)-8\cdot (1.548\,in)^{2}$

$S = 164.830\,in^{2}$

4 0

3 years ago

Determine the intercepts of the line. yy y y -intercept: (\Big( ( left parenthesis ,, , comma )\Big) ) right parenthesis xx x x

BlackZzzverrR [31]

Question:

Give all the x and y intercept of the function

$f(x) = \frac{3x^2 - 3x-60}{2x^3 + 2x^2-34x+30}$

Answer:

The x intercepts are x = 5 and x = -4

The y intercept is at y = -2

Step-by-step explanation:

Factorizing the numerator of the expression we find the x intercepts as follows;

$f(x) = \frac{3x^2 - 3x-60}{2x^3 + 2x^2-34x+30} =\frac{3(x-5)(x+4)}{2x^3 + 2x^2-34x+30}$

Therefore, the x intercept are

x = 5 and x = -4

To find the y intercept, we put x = 0 to get y = -2

Therefore, the y intercept is at y = -2

Factorizing the denominator we find the values for which the equation is undefined

2·x³ + 2·x² - 34·x + 30 = 2·(x-1)·(x-3)·(x+5) which gives

x = 1, 3 and -5.

4 0

3 years ago

The word problem below has too little information. Read carefully, then

JulsSmile [24]

Answer:

A and D are needed

3 0

3 years ago

Help me with the question in the pic

Nonamiya [84]

Answer:

208

Step-by-step explanation:

With shapes like these, it's easier to break it into two squares. Area is width times height, and you know the taller square has a width of 6 and height of 16, so the area of that would be 96.

For the other square, subtract the 6 from the 14 to get the width, 8. For the height, subtract the 2 from the 16, and you get 14. 14x8 is 112.

Now add the two areas together, and you get 208.

3 0

3 years ago

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Evaluate s=7 a=5 m=3 t=4

Ksenya-84 [330]

What is the equation

8 0

4 years ago