The speed of the ball is
ds/dt = 32t
At t =1/2 s
ds/dt = 16 ft/s
The distance from the ground
50 - 16(1/2)^2 = 46 ft
The triangles formed are similar
50/46 = (30 + x)/x
x = 345 ft
50 / (50 - s) = (30 + x)/x
Taking the derivative and substituing
ds/dt = 16
and
Solve for dx/dt
Answer:
B
a circle with a diameter of 19.3 inches
Answer:
{4 + 2√3, 4 - 2√3} thus the solution is A. x = 4 + 2 sqrt(3) or x = 4 - 2 sqrt(3)
Step-by-step explanation:
Solve for x over the real numbers:
(x - 4)^2 = 12
Take the square root of both sides:
x - 4 = 2 sqrt(3) or x - 4 = -2 sqrt(3)
Add 4 to both sides:
x = 4 + 2 sqrt(3) or x - 4 = -2 sqrt(3)
Add 4 to both sides:
Answer: x = 4 + 2 sqrt(3) or x = 4 - 2 sqrt(3)
Answer C
When you multiply that together (c), it gives you p^2, -5p, -2p, and 10. Add the -5-2, and it gives you -7, or the original equation.
