yo i dont know the answer but i hope you have a good day
I attached a couple below pictures with all the work and a bit more information to help you understand the problem.
I hope this helps! If you have any questions, just comment them below :)
Answer:
C) 2094.40
nearest answer.
Step-by-step explanation:
Since the given region is bounded by y = x, y = 10 and x = 0
⇒ 0 ≤ y ≤ 10
Radius and Height are 'y'
∴ The required volume
= ∫₀¹⁰2π(radius)(height)dy
= ∫₀¹⁰2π (y) (y) dy
= ∫₀¹⁰2π y² dy
= 2π ∫₀¹⁰ y² dy
Integrate y
= ![2\pi [\frac{y^3}{3}]_0^{10}](https://tex.z-dn.net/?f=2%5Cpi%20%5B%5Cfrac%7By%5E3%7D%7B3%7D%5D_0%5E%7B10%7D)
= ![2\pi [\frac{10^3}{3} - 0]](https://tex.z-dn.net/?f=2%5Cpi%20%5B%5Cfrac%7B10%5E3%7D%7B3%7D%20-%200%5D)
= 
where π is 3.142
= 2,094.66