Answer:
Go catipiller
Step-by-step explanation:
Answer:
Triangles ABC and DEF have the following characteristics :B and E are right angles A=D, BC=EF which congruence theorem can be used to prove ABC =DEF
Answer:
True.
Step-by-step explanation:
For example let f(x) = 3x + 1 then f-1(x) is found as follows
Let f(x) = y = 3x + 1 then
3x = y - 1
x = (y-1) / 3
x = f-1(x) = (x - 1)/3.
So:
Replacing the x in y by (x - 1)/3 :-
x = f(-1)(y) = ( (3x + 1) - 1) / 3
= 3x / 3
= x.
So y = f(x).
First we'll do two basic steps. Step 1 is to subtract 18 from both sides. After that, divide both sides by 2 to get x^2 all by itself. Let's do those two steps now
2x^2+18 = 10
2x^2+18-18 = 10-18 <<--- step 1
2x^2 = -8
(2x^2)/2 = -8/2 <<--- step 2
x^2 = -4
At this point, it should be fairly clear there are no solutions. How can we tell? By remembering that x^2 is never negative as long as x is real.
Using the rule that negative times negative is a positive value, it is impossible to square a real numbered value and get a negative result.
For example
2^2 = 2*2 = 4
8^2 = 8*8 = 64
(-10)^2 = (-10)*(-10) = 100
(-14)^2 = (-14)*(-14) = 196
No matter what value we pick, the result is positive. The only exception is that 0^2 = 0 is neither positive nor negative.
So x^2 = -4 has no real solutions. Taking the square root of both sides leads to
x^2 = -4
sqrt(x^2) = sqrt(-4)
|x| = sqrt(4)*sqrt(-1)
|x| = 2*i
x = 2i or x = -2i
which are complex non-real values
Yes it is linear
It is a negative slope
I am attaching pic of graph
The slope is -3/4
Y intercept is (0,2)
