Answer:
How do you figure out if a relation is a function? You could set up the relation as a table of ordered pairs. Then, test to see if each element in the domain is matched with exactly one element in the range. If so, you have a function!
Step-by-step explanation:
Distance=amount of gas times miles per gallon
distance=y
amount of gas=x
mpg=?
given
y=300
x=10
300=10 times ?
divide both sidesj by 10
30=?
equation is
y=x times 30 or
y=30x
Answer:
25%
Step-by-step:
Convert fraction (ratio) 15 / 60 Answer: 25%
Answer:
defendant who, before being served with process, timely returns a waiver need not serve an answer to the complaint until 60 days after the request was sent—or ...
Step-by-step explanation:
<h3>Answer:</h3>
x/tan(x) is an even function
sec(x)/x is an odd function
<h3>Explanation:</h3>
<em>x/tan(x)</em>
For f(x) = x/tan(x), consider f(-x).
... f(-x) = -x/tan(-x)
Now, we know that tan(x) is an odd function, so tan(-x) = -tan(x). Using this, we have ...
... f(-x) = -x/(-tan(x)) = x/tan(x) = f(x)
The relation f(-x) = f(x) is characteristic of an even function, one that is symmetrical about the y-axis.
_____
<em>sec(x)/x</em>
For g(x) = sec(x)/x, consider g(-x).
... g(-x) = sec(-x)/(-x)
Now, we know that sec(x) is an even function, so sec(-x) = sec(x). Using this, we have ...
... g(-x) = sec(x)/(-x) = -sec(x)/x = -g(x)
The relation g(-x) = -g(x) is characeristic of an odd function, one that is symmetrical about the origin.