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ioda
3 years ago
15

I feel like I am asking so my questions but I dont really care its a Sunday xD

Mathematics
2 answers:
dimulka [17.4K]3 years ago
4 0
You would add like terms so it would be 1x then you add 1 to 7 so you would get 8.. the you divide both sides by 1x and you'd get 8=x
zepelin [54]3 years ago
4 0

Answer:  x = 8

−2x − 1 + 3x =7

−2x + −1 + 3x =7

(−2x+3x) + (−1) =7 (Combine Like Terms)

x+ −1 =7

x−1=7

Step 2: Add 1 to both sides.

x−1+1=7+1

x=8

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Find the ordered pairs for the x- and y-intercepts of the equation 5x − 6y = 30 and select the appropriate option below.
Amiraneli [1.4K]
5x - 6y = 30
6y = 5x - 30
Y = 5/6x - 5
y intercept = -5
Therefore (0, -5)

0 = 5/6x - 5
5/6x = 5
x = 6
x intercept = 6
therefore (6,0)

answer : first one 
x intercept =
7 0
4 years ago
Read 2 more answers
1. Ted found out that the rebate is not given until after he has
nadezda [96]

9514 1404 393

Answer:

  maybe not

Step-by-step explanation:

Consider a couple of scenarios for a $20,000 car purchase and a $2000 rebate, with sales tax at 10%.

1) The rebate is applied directly to the purchase price.

  Taxable amount: $20,000 -2,000 = $18,000.

  Price with tax: $18,000 × 1.10 = $19,800

  Amount financed: $19,800.

__

2) The rebate is given after the sale is complete.

  Taxable amount: $20,000

  Price with tax: $20,000 × 1.10 = $22,000

  Amount financed: $22,000

  Remaining loan balance if $2000 rebate is immediately applied to the loan: $22,000 -$2000 = $20,000

__

If the loan is for 5 years at 3%, the payments and total costs are ...

  Scenario 1: Monthly payment $355.78;

     total cost of loan: 60×355.78 = 21,346.80

  Scenario 2: Monthly payment $395.31;

     total cost of loan: 55×395.31 = $21,742.05  (note there are fewer payments because of the initial payment to principal of $2000)

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Ted effectively has to finance an additional $200, equal to the sales tax on the rebate. So the delayed rebate costs him an extra $395.25 over the life of the loan.

_____

We have assumed certain tax and payment scenarios. If tax is not an issue, and if the loan terms are such that the rebate can be applied immediately to the loan amount, then <em>there may be no difference in total cost</em>, or the delayed rebate may result in a <em>lower</em> total cost due to the higher monthly payment.

7 0
3 years ago
Help! Find the domain of the graph
charle [14.2K]

Answer:

[-8,4]

Step-by-step explanation:

you look at the x-axis. The end points of the graph are -8 and 4, thus the domain would be [-8,4] as it is always written in left to right or bottom to top value.

hope it helps.

8 0
3 years ago
"A cable TV company wants to estimate the percentage of cable boxes in use during an evening hour. An approximation is 20 percen
Marizza181 [45]

Answer:

The company should take a sample of 148 boxes.

Step-by-step explanation:

Hello!

The cable TV company whats to know what sample size to take to estimate the proportion/percentage of cable boxes in use during an evening hour.

They estimated a "pilot" proportion of p'=0.20

And using a 90% confidence level the CI should have a margin of error of 2% (0.02).

The CI for the population proportion is made using an approximation of the standard normal distribution, and its structure is "point estimation" ± "margin of error"

[p' ± Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }]

Where

p' is the sample proportion/point estimator of the population proportion

Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} } is the margin of error (d) of the confidence interval.

Z_{1-\alpha /2} = Z_{1-0.05} = Z_{0.95}= 1.648

So

d= Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }

d *Z_{1-\alpha /2}= \sqrt{\frac{p'(1-p')}{n} }

(d*Z_{1-\alpha /2})^2= \frac{p'(1-p')}{n}

n*(d*Z_{1-\alpha /2})^2= p'(1-p')

n= \frac{p'(1-p')}{(d*Z_{1-\alpha /2})^2}

n= \frac{0.2(1-0.2)}{(0.02*1.648)^2}

n= 147.28 ≅ 148 boxes.

I hope it helps!

3 0
4 years ago
8.71 ×<img src="https://tex.z-dn.net/?f=10%5E%7B7%7D" id="TexFormula1" title="10^{7}" alt="10^{7}" align="absmiddle" class="late
Semmy [17]
It’s 87100000 Have Ah Good Day.
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3 years ago
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