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cupoosta [38]
3 years ago
12

What’s the answer?!?

Mathematics
2 answers:
fiasKO [112]3 years ago
8 0
Ok the answer is really the 1st one not the 3rd one for real sorry

Stels [109]3 years ago
3 0
The area of the triangle is 50in2, so she can create only 2 triangles.
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-2(2x-5)=-74 show all work pleaseeeee 15 points!
frutty [35]

Answer:

x equals 4

Step-by-step explanation:

3 0
3 years ago
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A hyperbola centered at the origin has verticies at (add or subtract square root of 61,0 and foci at (add or subtract square roo
deff fn [24]

Answer:

\frac{x^2}{61}-\frac{y^2}{37}  =1

Step-by-step explanation:

The standard equation of a hyperbola is given by:

\frac{(x-h)^2}{a^2} -\frac{(y-k)^2}{b^2} =1

where (h, k) is the center, the vertex is at (h ± a, k), the foci is at (h ± c, k) and c² = a² + b²

Since the hyperbola is centered at the origin, hence (h, k) = (0, 0)

The vertices is (h ± a, k) = (±√61, 0). Therefore a = √61

The foci is (h ± c, k) = (±√98, 0). Therefore c = √98

Hence:

c² = a² + b²

(√98)² = (√61)² + b²

98 = 61 + b²

b² = 37

b = √37

Hence the equation of the hyperbola is:

\frac{x^2}{61}-\frac{y^2}{37}  =1

6 0
3 years ago
-10(1+4n)-8 I NEED HELP PLSSSSSSS!!!
kirill [66]
-10-40n-8
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2(-9-20n)
5 0
3 years ago
A piece of art is in the shape of an equilateral triangle with sides of 25in. Find the area of the piece of art. Round your answ
mojhsa [17]
A=\sqrt{3}/4 * side length^2
A=270.663
The answer is B.
6 0
3 years ago
Read 2 more answers
The venticles of a right angle are a[0,4], b[3,-2] c[-3, -4] Find It's area.​
givi [52]

Answer:

The area of this triangle is about 21.2132 square units.

Step-by-step explanation:

First, find the lengths of the legs AB and BC.

Length of AB ===

Find the difference in position vertically:

-2-4=-6

The points are 6 units apart vertically.

Find the difference in position horizontally:

3-0=3

The points are 3 units apart horizontally.

These lengths form a right triangle with the distance between the points as the hypotenuse, so you can use the pythagorean theorem to solve:

a^2+b^2=c^2\\3^2+6^2=c^2\\9+36=c^2\\45=c^2\\c\approx6.7082

AB is about 6.7082 units long.

Length of BC ===

Same process as above.

Find the vertical distance:

-4--2=-2

2 units apart vertically.

Find the horizontal distance:

-3-3=-6

6 units apart horizontally.

Use the pythagorean theorem:

2^2+6^2=c^2\\4+36=c^2\\40=c^2\\c=6.3246

BC is about 6.3246 units long.

Area ===

Finally, you can use these to find the area of the triangle. The area of a right triangle is just half the area of a rectangle with the same base and height:

A=\frac{b\times h}{2}\\\\A=\frac{6.7082\times6.3246}{2}\\\\A=\frac{42.4264}{2}\\\\A=21.2132

The area of this triangle is about 21.2132 square units.

4 0
3 years ago
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