Nooooooooooooooooooooooooo
Answer: All real numbers less than or equal to 3.
Explanation: I took a test with this question and got it right.
The expected length of code for one encoded symbol is
where 
is the probability of picking the letter 
, and 
is the length of code needed to encode . is given to us, and we have
so that we expect a contribution of
bits to the code per encoded letter. For a string of length 
, we would then expect ![E[L]=1.375n](https://tex.z-dn.net/?f=E%5BL%5D%3D1.375n)
.
By definition of variance, we have
![\mathrm{Var}[L]=E\left[(L-E[L])^2\right]=E[L^2]-E[L]^2](https://tex.z-dn.net/?f=%5Cmathrm%7BVar%7D%5BL%5D%3DE%5Cleft%5B%28L-E%5BL%5D%29%5E2%5Cright%5D%3DE%5BL%5E2%5D-E%5BL%5D%5E2)
For a string consisting of one letter, we have
so that the variance for the length such a string is
"squared" bits per encoded letter. For a string of length , we would get ![\mathrm{Var}[L]=1.859n](https://tex.z-dn.net/?f=%5Cmathrm%7BVar%7D%5BL%5D%3D1.859n)
.
The new exponential equations to represent Alison, Cindy, and Javier would be 1/(1+e^-x) representing an s curve showing a lot of growth.
<h3>What is an exponential equation?</h3>
The exponential function is a mathematical function denoted by f(x)=\exp or e^{x}.
Here, he new exponential equations to represent Alison, Cindy, and Javier would be 1/(1+e^-x) representing an s curve showing a lot of growth while Cindy and Javier would be ln(x) and x^(1/2) as they will grow somewhat fast at first and then die out.
Learn more about equations on:
brainly.com/question/2972832
#SPJ1
9514 1404 393
Answer:
23.44
Step-by-step explanation:
The mnemonic SOH CAH TOA reminds you of the relation ...
Tan = Opposite/Adjacent
tan(38°) = x/30
x = 30·tan(38°) ≈ 23.4386
x ≈ 23.44
