Csc(x) = 1/sin(x)
sec(x) = 1/cos(x)
cot(x) = [1/sin(x)] / [1/cos(x)]
cot(x) = 1/sin(x) * cos(x)/1
cot(x) = cos(x) / sin(x)
cot(x) = cot(x)
-2(-5x+9)-9x
-2(-5x)+-2(9)-9x
10x-18-9x
+9 +9
19x=-18
---- ----
19 19
x=-1.05
Answer:
im confussed
Step-by-step explanation:
Answer:
3.5 hours
Step-by-step explanation:
Speed of train X=30 mph
Speed of train Y=40 mph
Relative speed When the two trains travelling in same direction
Relative speed=40-30=10 mph
Total distance =25+10=35 miles
We have to find the time when train Y is 10 miles ahead of train X.
We know that
Time=
Using the formula
Then, we get
Time=
Hence, it will be 3.5 hours until train Y is 10 miles ahead of train X.
Answer:
Joey sold 6 cars
Step-by-step explanation:
Joey earns $350 per week + $200 per car he sells
The number of cars that he sold last week is unknown, so represent it with a variable, x.
Write an equation
$350 + $200x = $1,550
Subtract $350 from both sides of this equation
$200x = $1200
Divide both sides of the equation by 200
x = 6
Joey sold 6 cars
Hope this helps :)