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1 year ago

How do you do this then? (higher tier maths GCSE)

Mathematics

1 answer:

olga_2 [115]1 year ago

3 0

Answer:

answer below

Step-by-step explanation:

when f(x+7)

moves the vertex to the LEFT not right

so the vertext would be (-5,-7)

when f(-x)

the graph is a reflection in y axis

so the vertex would be (-2,-3)

hope this helps!

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URGENT! WILL GIVE BRAINLY FOR CORRECT ANSWER

Minchanka [31]

Answer:

sorry if im wrong i think wrong numbers. plz check

Step-by-step explanation:

The center of dilation of the question is (-4,-3) .

let say that

x0=-4

y0=-3

Label the image A'B'C'

The new coordinate would be

A(-4,-1)

x=4

y=-1

x'=x0+ 2(x - x0)

x'= -4+ 2(-4 +4)

x'=-4

y'=y0+ 2(y - y0)

y'= -3+ 2(-1 +3)

y'=-3 +4= 1

______________________________

B(-4,-3)

x=-4

y=-3

x'=x0+ 2(x - x0)

x'= -4+ 2(-4 +4)

x'=-4

y'=y0+ 2(y - y0)

y'= -3+ 2(-3 +3)

y'=-3

______________________________

C(-1,-3)

x=-1

y=-3

x'=x0+ 2(x - x0)

x'= -4+ 2(-1 +4)

x'=-4 +6= 2

y'=y0+ 2(y - y0)

y'= -3+ 2(-3 +3)

y'=-3

A'(-4,1)

B'(-4,-3)

C'(2,-3)

3 0

2 years ago

F(x)=-5x+2 and g(x)=1/2x+4 find f(g(12))

skad [1K]

Answer:

- 48

Step-by-step explanation:

If you want to learn more about this concept, it's called composition of functions.

First, you plug in g(x) as if it were x into f(x).

f(g(x))= -5 (1/2x + 4) + 2

= -5/2x - 20 + 2

= -5/2x - 18

Then, plug in the value given, as x.

= -5/2 (12) - 18

= -30 - 18

= - 48

I hope this helped!

3 0

3 years ago

If a man hold his breath for three minutes and dies because of it what is that called

miss Akunina [59]

Answer:

Holding your breath is called static Apnea and a common person can't hold their breath for long. If a person holds their breath for long and dies because of it, it may be called lack of breath or lack of respiration.

6 0

3 years ago

The acceleration of an object (in m/s^2) is given by the function a(t) = 9 sin(t). The initial velocity of the object is v(0) =

pentagon [3]

a) Acceleration is the derivative of velocity. By the fundamental theorem of calculus,

$v(t)=v(0)+\displaystyle\int_0^ta(u)\,\mathrm du$

so that

$v(t)=\left(-11\frac{\rm m}{\rm s}\right)+\int_0^t9\sin u\,\mathrm du$

$\boxed{v(t)=-\left(2+9\cos t)\right)\frac{\rm m}{\rm s}}$

b) We get the displacement by integrating the velocity function like above. Assume the object starts at the origin, so that its initial position is $s(0)=0\,\mathrm m$ . Then its displacement over the time interval [0, 3] is

$s(0)+\displaystyle\int_0^3v(t)\,\mathrm dt=-\int_0^3(2+9\cos t)\,\mathrm dt=\boxed{-6-9\sin3}$

c) The total distance traveled is the integral of the absolute value of the velocity function:

$s(0)+\displaystyle\int_0^3|v(t)|\,\mathrm dt$

$v(t)$ for $0\le t$ and $v(t)\ge0$ for $\cos^{-1}\left(-\frac29\right)\le t\le3$ , so we split the integral into two as

$\displaystyle\int_0^{\cos^{-1}\left(-\frac29\right)}-v(t)\,\mathrm dt+\int_{\cos^{-1}\left(-\frac29\right)}^3v(t)\,\mathrm dt$

$=\displaystyle\int_0^{\cos^{-1}\left(-\frac29\right)}(2+9\cos t)\,\mathrm dt-\int_{\cos^{-1}\left(-\frac29\right)}^3(2+9\cos t)\,\mathrm dt$

$\displaystyle=\boxed{2\sqrt{77}-6+4\cos^{-1}\left(-\frac29\right)-9\sin3}$

4 0

2 years ago

I need help with geometry

GREYUIT [131]

9514 1404 393

Answer:

Step-by-step explanation:

Attached is a copy of the figure with some of the clutter removed. The congruent angles marked with a single arc, and the parallel lines are given.

The angles marked with a double arc are congruent because they are alternate interior angles where transversal XZ crosses parallel lines XW and YZ. Of course, side XZ is congruent to itself.

Hence we have two angles and a side not between them that are congruent. We can declare ∆XWZ ≅ ∆ZYX by the AAS postulate. (choice A)

6 0

2 years ago

How do you do this then? (higher tier maths GCSE)​

How do you do this then? (higher tier maths GCSE)