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Vladimir [108]
3 years ago
15

Need help ASAP!!!!! 14 points to answer with the correct explanation.

Mathematics
2 answers:
Ganezh [65]3 years ago
5 0
The person above me has the correct answer
Savatey [412]3 years ago
4 0

Step-by-step explanation:

A is the area of the triangle

A = (a.h)/2 = 10.14x12.2/2 = 61.854 m2

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Solve this equation<br> 3x^2 − 16x = x^2 − 30
ValentinkaMS [17]

3x^2-16x=x^2-30

-x^2        -x^2

2x^2-16x=-30

+30          +30

2x^2-16x+30=0

2x-6=0 or x-5=0

x=3    or x=5

A. 3,5

If you need an explanation, I can provide one. Hope it helped! If it didn't tell me what went wrong or what confused you.

3 0
2 years ago
Read 2 more answers
X over 45 - 7 over 9. X = ?
Degger [83]

Answer:

X=35

Step-by-step explanation:

simplify 7/9

x/45-7/9=0

simplify x/45

x - (7 • 5)/45=  x - 35/45

x-35/45=0

add 35  to both sides

x=35

I tried it's hard to write it all out on here i just to give u the best sorry :)

7 0
3 years ago
find the value of tan (a-b) if cos a=4/5 on the interval (270, 360) and sin b=-5/13 on the interval (270, 360)
Rudiy27

We can find a and b using inverse trig functions,

\cos(a)=\frac{4}{5}\implies a=\arccos\Big(\frac{4}{5}\Big)\approx36.87 \\\sin(b)=-\frac{5}{13}\implies b=\arcsin\Big(-\frac{5}{13}\Big)\approx-22.62

\tan(36.87-(-22.62))\approx1.7

Hope this helps.

7 0
3 years ago
The function f(x) = 4(4)x represents the growth of a fly population every year in a remote swamp. Jackie wants to manipulate the
otez555 [7]
Around the rate would be 0.10
4 0
3 years ago
Read 2 more answers
At time t=0 hours, a tank contains 3000 litres of water. Water leaks from the tank. At the end of every hour there is x% less wa
Margaret [11]

Answer:

x = 2; K = 0.98

Step-by-step explanation:

At time, t = 0, Volume of Water = 3,000 litres

After t hours , the Volume of water in the tank = Vt

At the end of every hour there is a x% less water in the tank then at the start of the hour

After 1 hour, volume of water left Vt = V1

V1 = 3,000 - 3000 × (x/100)

V1 = 3,000 - 30x

After 2 hours, Volume of water left is V2

V2 = (3,000 - 30 x) - (3,000 - 30 x) × (x/100)

V2 = (3,000 - 30 x) - (3000x - 30x²)/100

V2 = {100(3000 - 30x) - x(3000 - 30x)} /100

V2 = {(3000 - 30x)(100 - x)}/100

Recall, V2 = 2881.2

Therefore

{(3000 - 30x)(100 - x)}/100 = 2881.2

(3000 - 30x)(100 - x) = 288120

300000 - 3000 x - 3000 x + 30 x² = 288120

30 x ² - 6000 x + 11880 = 0

Dividing both sides by 30

x² - 200 x + 396=0

Factorizing:

(x -198)(x-2) = 0

x = 198 or x = 2

Since the percentage by which the water reduces cannot be greater than 100, x = 2 is chosen.

Step 2: Solving for k

Given that Vt=KtV0

K = Vt/V0

At t = 1

V1 = 3000 - 30x

V1 = 3000 - 30 × 2

V1 = 3000 - 60

V1 = 2940

K = 2940/3000

K = 0.98

5 0
3 years ago
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