Step-by-step explanation:
For g(x) = f(x) + 5:
Because f(x) = x, this can be simplified to:
y = x + 5
For h(x) = 2 * f(x) - 3, simplified to:
2*x - 3 or 2x - 3
For j(x) = 
, simplified it is
For f(x), this can be drawn relatively easy, it is a linear line starting at the coordinates (0,5) gradually increasing by 1 in both the y and x axis. It can be drawn parallel to the line given in your question just one above.
For h(x), the line will start at (0, -3) but then have an incline of 2, i.e. the second point would be at 1, -1, and the third at (3, 3). This is because you are doubling the value of x but subtracting 3.
For j(x), x is halved so the line will be less steep although it will start at the coordinate (0, -1) because 1 is being subtracted.
Hope this helps!
The direction of the vector is - 21.8 N of E , Option B is the answer.
<h3>What is a Vector ?</h3>
A vector is an object with both magnitude and direction.
A vector is shown in the graph.
To determine the direction , The angle needs to be determined
The slope of the vector will give the direction of the vector
The vector starts from the point (1 , 1)
Another point on the vector (-4 , 3)
slope = -2 /5
It is making angle x with the line y = 1
tan x = -2 /5
x = - 21.8 N of E.
Therefore the direction of the vector is - 21.8 N of E , Option B is the answer.
To know more about Vector
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Answer:
a= 37
Step-by-step explanation:
All the angles of a triangle add up to 180° so if you add 110 with 35 it equals 145, then subtract 145 by 180 and you get 37
they are not congruent because
the sides, and noncongruent means “not congruent,” that is, not the same shape. (Shapes that are reflected and rotated and translated copies of each other are congruent shapes.) So we want triangles that look fundamentally different. But this is just a congruent copy of the triangle we have up above on the left. is the correct answer
Rate for Sally is 1 room per 8hrs
rate for Steve is 1 room per 7hrs
combined rate:
1/8 + 1/7 = 1/T
7/56 + 8/56 = 1/T
15/56 = 1/T
56/15 = T
3 11/15 = 3 hrs 44 min
