If we know the three corresponding sides form the same ratio, then we can use the SSS similarity theorem
If we know that 2 pairs of angles are congruent, then we can use the AA similarity theorem
Finally, if we know that two sides are proportional with the congruent angles between the two sides, then we can use the SAS similarity theorem
See the attached for the final answers
Given:
m∠DAE = 30°
m∠CBE = 20°
To find:
The value of x.
Solution:
In rectangle, all angles are right angle.
m∠A = m∠B = m∠C = m∠D = 90°
m∠EDA + m∠EAB = 90°
30° + m∠EAB = 90°
m∠EAB = 90° - 30°
m∠EAB = 60°
Similarly, m∠CBE + m∠EBA = 90°
20° + m∠EBA = 90°
m∠EBA = 90° - 20°
m∠EBA = 70°
In triangle AEB,
Sum of all angles in a triangle = 180°
m∠EAB + m∠AEB +m∠EBA = 180°
60° + x° + 70° = 180°
130° + x° = 180°
Subtract 130° from both sides, we get
x° = 50°
x = 50
The value of x is 50.
Answer:
the 3rd one
Step-by-step explanation:
since it has a diameter of 28, then its radius must be half that or 14.
![\textit{area of a circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=14 \end{cases}\implies A=\pi (14)^2\implies A=196\pi ~\hfill \stackrel{\stackrel{semi-circle}{half~that}}{98\pi }](https://tex.z-dn.net/?f=%5Ctextit%7Barea%20of%20a%20circle%7D%5C%5C%5C%5C%20A%3D%5Cpi%20r%5E2~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D14%20%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Cpi%20%2814%29%5E2%5Cimplies%20A%3D196%5Cpi%20~%5Chfill%20%5Cstackrel%7B%5Cstackrel%7Bsemi-circle%7D%7Bhalf~that%7D%7D%7B98%5Cpi%20%7D)
Answer:
Step-by-step explanation:
The slope and the y intercept (you can tell there linear if the slope is the same and the y-intercepts are different).