Answer:
1. x/2=1.75/3.5 x=1
2. 4/2=y/3.5 y=3.5
3. P (Figure Left)=3+5+2+1+4+8+3+2=28 cm
A (Figure Left)=8x2-2x1-3x2=8 cm2
4. P (Figure Left) / P (Figure Right) = 1/1.75 = 28/ P (Figure Right)
P (Figure Right)= 49 cm
A (Figure Left) / A (Figure Right) = 1/1.752 = 8/ A (Figure Right)
A(Figure Right)= 24.5 cm2
Step-by-step explanation:
1. x/2=1.75/3.5 x=1
2. 4/2=y/3.5 y=3.5
3. P (Figure Left)=3+5+2+1+4+8+3+2=28 cm
A (Figure Left)=8x2-2x1-3x2=8 cm2
4. P (Figure Left) / P (Figure Right) = 1/1.75 = 28/ P (Figure Right)
P (Figure Right)= 49 cm
A (Figure Left) / A (Figure Right) = 1/1.752 = 8/ A (Figure Right)
A(Figure Right)= 24.5 cm2
Answer:
Match it with x and y method
Step-by-step explanation:
Given a group of
n object. We want to make a selection of
k objects out of the n object. This can be done in
C(n, k) many ways, where
,
where k!=1*2*3*...(k-1)*k
Thus, we can do the selection of 3 cd's out of 5, in C(5,3) many ways,
where
Answer: 10
Answer:
0.75
Step-by-step explanation:
Given,
P(A) = 0.6, P(B) = 0.4, P(C) = 0.2,
P(A ∩ B) = 0.3, P(A ∩ C) = 0.12, P(B ∩ C) = 0.1 and P(A ∩ B ∩ C) = 0.07,
Where,
A = event that the selected student has a Visa card,
B = event that the selected student has a MasterCard,
C = event that the selected student has an American Express card,
We know that,
P(A ∪ B ∪ C) = P(A) + P(B) + P(C) - P(A ∩ B) - P(A ∩ C) - P(B ∩ C) + P(A ∩ B ∩ C)
= 0.6 + 0.4 + 0.2 - 0.3 - 0.12 - 0.1 + 0.07
= 0.75
Hence, the probability that the selected student has at least one of the three types of cards is 0.75.
