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Ksju [112]
3 years ago
13

How many solutions does the following equation have? |3x + 12| = 18

Mathematics
2 answers:
svp [43]3 years ago
6 0
3x +12 = 18
-12 -12
---------------
3x 6
-- = --
3 3
x = 2
Anni [7]3 years ago
5 0
Hello,

if 3x+12>0 then |3x+12|=3x+12
so 3x+12=18==>3x=6==>x=2

if 3x+12<0 then |3x+12|=-(3x+12)=-3x-12
so -3x-12=18 ==>-3x=30==>x=-10

Two solutions!

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Answer:

original price = 105.66

Step-by-step explanation:

35% off means she pays 100-35 = 65%

original price * 65% = 68.68

Change to decimal form

original price *.65 = 68.68

Divide each side by .65

original price *.65/.65 = 68.68/ .65

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Step-by-step explanation:

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Add-on:

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HACTEHA [7]

Answer:

The null hypothesis was rejected.

Conclusion: The proportions of orders completed on the day of receiving is more than 95%.

Step-by-step explanation:

The hypothesis can be defined as:

<em>H₀</em>: The proportions of orders completed on the day of receiving is not more than 95%, i.e. <em>p</em> ≤ 0.95.

<em>Hₐ</em>: The proportions of orders completed on the day of receiving is more than 95%, i.e. <em>p</em> > 0.95.

The significance level of the test is <em>α</em> = 0.025.

The sample size is, <em>n</em> = 500.

As the sample size is large, the sampling distribution of sample proportion can be approximated by the Normal distribution.

The mean and standard deviation of this distribution are:

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The test statistic is:

z=\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n}} }

The sample proportion is:

\hat p=\frac{X}{n}=\frac{485}{500}=0.97

Compute the test statistic as follows:

z=\frac{0.97-0.95}{\sqrt{\frac{0.95(1-0.95)}{500}} }=2.05

The decision rule is:

If the <em>p</em>-value is less than the significance level <em>α</em> then the null hypothesis is rejected.

Compute the <em>p</em>-value as follows:

p-value=P(Z>2.05)\\=1-P(Z

*Use a <em>z</em>-table.

The <em>p</em>-value = 0.0202 < <em>α</em> = 0.025.

The null hypothesis will be rejected.

<u>Conclusion</u>:

As the null hypothesis was rejected at 2.5% level of significance, it can be concluded that the proportions of orders completed on the day of receiving is more than 95%.

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